Let width = w
Let length = l
Let area = A
3w+2l=1200
2l=1200-3w
l=1200-3/2
A=w*l
A=w*(1200-3w)/2
A=600w-(3/2)*w^2
If I set A=0 to find the roots, the maximum will be at wmax=-b/2a which is exactly 1/2 way between the roots-(3/2)*w^2+600w=0
-b=-600
2a=-3
-b/2a=-600/-3
-600/-3=200
w=200
And, since 3w+2l=1200
3*200+2l=1200
2l = 600
l = 300
The dimensions of the largest enclosure willbe when width = 200 ft and length = 300 ft
check answer:
3w+2l=1200
3*200+2*300=1200
600+600=1200
1200=1200
and A=w*l
A=200*300
A=60000 ft2
To see if this is max area change w and l slightly but still make 3w+2l=1200 true, like
w=200.1
l=299.85
A=299.85*200.1
A=59999.985
Since DC = 12, then EF also = 12.
Both AD and BC are indicated to be the same .
So AE = (24 - 12) / 2 = 12/2 = 6
Now you have a right triangle with height DE = 8 and base AE = 6
Using the Pythagorean Theorem we can now find AD:
AD = √(8^2 + 6^2)
AD = √(64 + 36)
AD =√100
AD = 10
1. true
2. false
3. true
4. false
5. true
Answer:
8 and 6 is the answer.......
Answer:
D
Step-by-step explanation:
Its decaying since its being multiplied by by a number less than 1
