Answer:
hence g(x) is increasing at point x= 3+14i,3-14i
Step-by-step explanation:
given, g(x)=x^3-(8+1)x^2-4(9+2)x+5x2-1
g(x)=x^3-9x^2-44x+10x-1
g(x)=x^3-9x^2-34x-1
=3x^2-18x-34
for increasing and decreasing function,
3x^2-18x-34=0
x=3+14i
0
x=3-14i
0
hence g(x) is increasing at point x= 3+14i,3-14i answer
The range is 10 to 40 and then the rest .
Hoped I helped by have a create day!okemzkzkkdkxdkjxkfjjzkekkdkekzkdkdkdkdiididididiididiididodododo
The mistake is P-21=34
It should be p+21=34
P=34-21
P=13
For a given degree of the polynomial, the number of turning points is given by n-1, where n is the degree of the polynomial. A polynomial that has x number of zeros is a polynomial of degree x. Thus the polynomial that has 9 zeros and 4 turning points, is a polynomial of degree 9.