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fomenos
3 years ago
6

If y varies inversely with x and y is 10 when x is 5, then what is y when x is 2?

Mathematics
1 answer:
Jobisdone [24]3 years ago
6 0

9514 1404 393

Answer:

  25

Step-by-step explanation:

Inverse variation means ...

  y = k/x

For the given values, we can find k to be ...

  k = xy = (5)(10) = 50

Then for x=2, we have ...

  y = 50/x

  y = 50/2

  y = 25 . . . when x=2

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The Reyes want grilled chicken and tilapia for dinner. Mrs.
seropon [69]

Answer:

Kilogram of chicken = 1

Kilogram of tilapia = 3

Step-by-step explanation:

Cost of chicken = 150 per kilo

Cost of tilapia = 100 per kilo

Number of kilos of each if total cost should not exceed 450

Let :

Number of kilo of chicken = x

Number of tilapia kilo = y

The constraint :

150x + 100y ≤ 450

We could choose some reasonable values of x and y then, test the constraint ;

If x = 1 and y = 3

150(1) + 100(3) = 450

Hence,

1 kilo of chicken with 3 kilos of tilapia offers the greatest combination of Number of kilograms of tilapia and chicken that could be purchased and still satisfy the maximum cost constraint.

6 0
3 years ago
How I can answer this question, NO LINKS, If you answer correctly I will give u brainliest!
Vikentia [17]

Answer:

\huge\boxed{\sf n = 7}

Step-by-step explanation:

<u>Given equation is:</u>

(7^2)^4=n^8

Multiply 2 to 4

7^8=n^8

While comparing both sides, we get:

7 = n

OR

n = 7

\rule[225]{225}{2}

Hope this helped!

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7 0
3 years ago
Read 2 more answers
5(k+5)+4&lt;21+6k what is the answer
Temka [501]
Solve whats in the parentheses first
5k+25+4<21+6k

5k+29<21+6k

plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27

5(2)+29<21+6(2)
10+29<21+12
39<33

so 5(k+5)+4 is greater than 21+6k
4 0
3 years ago
Uf bguvhbacndkzvhsdvnjsdbsdvbs help
bagirrra123 [75]

Answer:

3 + 2 = 5

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Step-by-step explanation:

Solve in parenthesis first then do exponents then perform the subtraction.

Using PEMDAS it will be a LOT more easier.

6 0
3 years ago
Read 2 more answers
find three consecutive odd integers such that the sum of the middle and largest integer is 21 more than smallest integer. ​
mina [271]

Answer:

15, 17, 19

Step-by-step explanation:

8 0
3 years ago
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