Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
Answer: a^2x^2+9x^2+13x+6a
Step-by-step explanation:
(a^2+9) x^2+ 13x +6a
x^2(a^2+9)+13x+6a
Expand:x^2(a^2+9): a^2 x^2+9^2
x^2 a^2 +x^2*9
a^2 x^2+9x^2
a^2 x^2+9x^2+13x+6a
If you calculate 240/48, you will get 5 without any remainder, which means if you get 5 buses it can exactly take all students?
Answer:
reflection on the y axis
Step-by-step explanation:
it flips from side to side
First isolate x by multiplying by x on both sides. It will look like this:
(2/3)x=1.2
Then devise by (2/3) on both sides to get:
x= 1.2/(2/3)
The easiest way to get this is plug that into a calculator and get the answer:
x=1.8
