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r-ruslan [8.4K]
3 years ago
11

(3x+2) and (5x-6) solve for x

Mathematics
1 answer:
HACTEHA [7]3 years ago
6 0

Answer:

x=3X 2 + 5x -6

Step-by-step explanation:

3X2 + 5X-6= 3X2 + 5X 6

X=3X2 +5X -6

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2(-2-4) = use the distributive property to expand the expression below.
Doss [256]

Answer:

-12

Step-by-step explanation:

First, solve in parentheses.

2(-2-4)

=

2(-6)

Next, multiply 2 by -6.

Which equals -12.

So therefore using the distributive property shown above, the answer would be -12.

6 0
2 years ago
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For each equation, determine whether it represents a direct variation, an inverse variation, or neither. Find the constant of va
rewona [7]
Both inverse variation’s. K=constant=9,6
6 0
3 years ago
Pls help me guys :( you guys are talented
4vir4ik [10]
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5 0
3 years ago
What is 5C3?<br> A. 35<br> B. 10<br> C. 14<br> D. 28
galben [10]

Answer: B. 10

-5C3 or 5 choose 3 refers to how many combinations are possible from 5 items, taken 3 at a time. To calculate combinations, we will use the formula nCr = n! / r! ... * (n - r)!, where n represents the total number of items, and r represents the number of items being chosen at a time.

-10 is the total number of all possible combinations for choosing 3 elements at a time from 5 distinct elements without considering the order of elements in statistics & probability surveys or experiments. The number of combinations for sample space 5 CHOOSE 3 can also be written as 5C3 in the format of nCr or nCk.

Step-by-step explanation: Hope this help :D

5 0
2 years ago
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I have 10 goats, n of which are male. I need to choose 2 of them to make a casserole.
snow_tiger [21]

Answer: There are 4 male goats.

Step-by-step explanation:

We know that n of the 10 goats are male.

The probability that in a random selection, the selected goat is a male, is equal to the quotient between the number of male goats (n) and the total number of goats (10)

The probability is;

p = n/10

Now the total number of goats is 9, and the number of male goats is n -1

then the probability of selecting a male goat again is:

q = (n-1)/9

The joint probability (the probability that the two selected goats are male) is equal to the product of the individual probabilities, this is

P = p*q = (n/10)*((n-1)/9)

And we know that this probability is equal to 2/15

Then we have:

(n/10)*((n-1)/9) = 2/15

(n*(n-1))/90 = 2/15

n*(n-1) = 90*2/15 = 12

n^2 - n = 12

n^2 - n - 12  = 0

This is a quadratic equation, we can find the solutions if we use Bhaskara's formula:

For an equation:

a*x^2  + b*x + c =  0

The two solutions are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

For our case, the solutions will be:

n = \frac{1 +- \sqrt{(-1)^2 - 4*1*(-12)} }{2*1 } = \frac{1+- 7}{2}

The two solutions are:

n = (1 - 7)/2 = -3    (this solution does not make sense, we can not have a negative number of goats)

The other solution is:

n = (1 + 7)/2 = 4

This solution does make sense, this means that we have 4 male goats.

5 0
2 years ago
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