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frosja888 [35]
3 years ago
15

9 to the second power multiply by 3 to the 6 power =3 to the ? power

Mathematics
1 answer:
GenaCL600 [577]3 years ago
7 0

Answer:

Step-by-step explanation:

a^{m} × a^{n} = a^{m+n}

(a^{m})^{n} = a^{mn}

~~~~~~~~~~~~~

9^{2} × 3^{6} = (3²)² × 3^{6} = 3^{2*2+6} = 3^{10}

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To solve this problem you must apply the proccedure shown below:

1. You have that y varies jointly as x and z and inversely as the product of w and​ p. Therefore, you can write the following equation, where k is the constant of proportionality:

y=k(\frac{xz}{wp} )

2. Now, you must solve for the constant of proportionality, as following:

k=\frac{ywp}{xz}

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Which expression is equivalent to square root 55x^7y6/11x^11y^8
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\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}

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=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}

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