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marissa [1.9K]
2 years ago
13

Yo can smb tell me if this scatter plot is linear or non linear ?

Mathematics
1 answer:
vagabundo [1.1K]2 years ago
4 0

Answer:

scatter plotttt

Step-by-step explanation:

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The coordinates of trapezoid ABCD are A(−4, 3), B(2, 3), C(4, −1) and D(−4, −1). A line segment runs through the trapezoid with
madam [21]
The distance from point Y to the y-axis is 4 units and the distance from point Z to the y-axis is 3 units, then the lelgth of the segment YZ is 4+3=7 units.
If <span>a scale factor is 3, then the length of Y'Z' will be 7·3=21 units.
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P.S. In the added picture you can see trapezoid ABCD that was dilated by a scale factor 3 about the origin. This may help to understand that all linear values after dilation become multiplied by scale factor.
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3 years ago
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Rita earns $16.00 per hour. If she gets a 3% raise, what will be her new hourly wage?
Vikentia [17]
All percentages can be expressed as fractions or decimals. To find a percentage of a number, we multiply the percentage with the number. In this case:
3/100 * 16/1 = 48/100 = 0.48
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Her new hourly wage would be $16.48
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In early 2012, the Pew Internet and American Life Project asked a random sample of U.S. adults, "Do you ever ... use Twitter or
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Answer:

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And the confidence interval is given by:

(0.123, 0.177)

And for this case the interval contains the value 0.16, so then we can conclude at 5% of significance that the true proportion is not different from 0.16

3 0
3 years ago
HELLO<br><br> HELP<br><br> THANKS<br><br> BYE
seropon [69]
C) 5.5 thats what I got.
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3 years ago
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Expand 2(x-1) <br> Expand 3(2x+3)<br> Expand 7(x+5) <br> Expand 5(2x-y)
Agata [3.3K]
Those are the answers
2x-2
6x+9
7x+35
10x-5y
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2 years ago
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