Answer:
Solution Let E1 be the event that coin 1 is selected and E2 the event that coin 2 is selected. Let F be the event that exactly 7 of the 10 flips lands on heads, let G be the event that the fist flip is heads.
w - width
6w - length
486 in² - area of the rectangle
(w)(6w) = 6w² - area of the rectangle
The equation:
6w² = 486 <em>divide both sides by 6</em>
w² = 81 → w = √81
w = 9 in
l = 6w → l = (6)(9) → l = 54 in
The perimeter: P = 2l + 2w
P = 2(54) + 2(9) = 108 + 18 = 126 in
<h3>Answer: The perimeter is 126in</h3>
To be honest I dont really understand this question... if i did i would answer but... i love horses xp
Each of those angles are Inscribed angles. A useful fact is that the measure of the intercepted arc of an inscribed angle is twice the measure of the angle.
The intercepted arc of ∠C is arc BED. The intercepted arc of ∠E is arc BCD.
m(arc BED) + m(arc BCD) = 2( m∠C + m∠E)
The two arcs combined make u p the entire circle, so the sum of their measures is 360.
360 = 2(m∠C + m∠E)
180 = m∠C + m∠E
The angles are supplementary.
