Answer:
Step-by-step explanation:ok
we know the circumference shown for that picture is π miles, what would it be for the diameter? namely how long is the diameter of that circle whose circumference is π miles?
![\bf \textit{circumference of a circle}\\\\ C=\pi d~~ \begin{cases} d=diameter\\ \cline{1-1} C=\pi \end{cases}\implies \pi =\pi d\implies \cfrac{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{~~\begin{matrix} \pi \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}=d\implies 1=d](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bcircumference%20of%20a%20circle%7D%5C%5C%5C%5C%20C%3D%5Cpi%20d~~%20%5Cbegin%7Bcases%7D%20d%3Ddiameter%5C%5C%20%5Ccline%7B1-1%7D%20C%3D%5Cpi%20%5Cend%7Bcases%7D%5Cimplies%20%5Cpi%20%3D%5Cpi%20d%5Cimplies%20%5Ccfrac%7B~~%5Cbegin%7Bmatrix%7D%20%5Cpi%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%7B~~%5Cbegin%7Bmatrix%7D%20%5Cpi%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%7D%3Dd%5Cimplies%201%3Dd)
There you go. I just drew it to make it easier than giving coordinates
|2x + 12| = 18
First, break down the problem into 2 equations . / 2x + 12 = 18 and -(2x + 12) = 18
Second, solve the first equation. /

Subtract 12 from both sides. /

Subtract 18 - 16. /

Divide both sides by 2. /

Simplify. /
Third, solve the second equation. / -(2x + 12) = 18
Simplify your brackets. /

Add 12 to both sides. /

Add 18 + 12. /

Divide both sides by -2. /

Simplify. /

Simplify. /
Fourth, collect the solutions. /

Answer:
x = -15, 3
Isnt it 2.5 and ur welcome