Answer: i guess the problem is with P(x) => "x = ", then P(x) is true if that equality is true, and is false if the equality is false.
so lets see case for case.
a) x = 0, and = 0. So p(0) is true.
b) x = 1 and = 1, so P(1) is true.
c) x = 2, and = 4, and 2 ≠ 4, then P(2) is false.
d) x= -1 and = 1, and 1 ≠ -1, so P(-1) is false.
Answer:
Ella grew of an inch more
Step-by-step explanation:
For this problem, you want to subtract Ben's growth from Ella's.
This expression would be -
.
To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).
In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by and the second by
.
This makes the expression -
, which equals
.
**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!