2 years ago

What is the lengths of all 3?

Mathematics

1 answer:

Dmitrij [34]2 years ago

4 0

Answer:

AB=15

AC=15 as an isosceles triangle base arm

BC=4

Step-by-step explanation:

TO find value of (X)

take bath base arm

2x-1=X+7

2x-x=7+1

X=8

now

put value of (X)

AB= X+7= 8+7=15

AC=15 as an isosceles triangle base arm because both arm should be equal

AC=2X-1=2*8-1=15

BC= X-4=8-4=4

it may help you(:

You might be interested in

Find the difference: -2/5-(-4/5)

CaHeK987 [17]

Answer:

2/5

Step-by-step explanation:

-2/5-(-4/5) (remove the parentheses)

-2/5+4/5 (calculate)

solution: 2/5

hope this helps!

5 0

2 years ago

A band to played 3 concerts and earned about a total of $321.00.the band earned about the same amount for each concert estimate

Darya [45]

All you have to do is divide 321 by 3 to get $107.00 each night

8 0

2 years ago

Read 2 more answers

Help me give alot of pointz

VashaNatasha [74]

Answer:

1. 2560000

2. 256000

3. 256000

4. 2560000

7 0

1 year ago

Read 2 more answers

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago

What are the coordinates of the vertex of the parabola described by the

ICE Princess25 [194]

Step-by-step explanation:

please type the question properly

3 0

2 years ago

Read 2 more answers