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3 years ago

-9p-17=10 pls help I do Connexus

Mathematics

1 answer:

marshall27 [118]3 years ago

7 0

P would equal negative three.

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Isaac invested $1,800 in an account paying an interest rate of 4.7%

bazaltina [42]

Answer:

$3584.86 or 3600 if rounded to the nearest 100 dollars

Step-by-step explanation:

1800(1.047)^15= 3584.86

you can plug this into a calculator

7 0

3 years ago

Read 2 more answers

The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). Which represents g(x)?

Alenkinab [10]

For this case, the parent function is given by:

$f (x) = x ^ 2$

We apply the following transformations:

Vertical translations:

Suppose that k> 0

To graph y = f (x) + k, move the graph of k units upwards:

For k = 9 we have:

$h (x) = x ^ 2 + 9$

Horizontal translations:

Suppose that h> 0

To graph y = f (x-h), move the graph of h units to the right

For h = 4 we have:

$g (x) = (x-4) ^ 2 + 9$

Answer:

The function g (x) is given by:

$g (x) = (x-4) ^ 2 + 9$

7 0

3 years ago

Read 2 more answers

5 Vince draws the figures below. He says each figure has an area of 8 square units. Is he correct? Decide if each figure has an

igor_vitrenko [27]

Answer:ok so it is 1 A 2C 3 F 4H

Step-by-step explanation:

6 0

2 years ago

How do you break apart the factor 42 using place values

VLD [36.1K]

Let's break apart 42.

The 4 is in the tens. The 2 is in the ones.

Place Value starting from Thousands

Thousands Hundreds Tens Ones

_________ ________ ____ _____

4 2

So this is how we break up numbers using place value.

Hope this helps!

5 0

3 years ago

At Prairieview Middle School, 100 students participate in at least one of three after-school clubs: soccer club, art club, and g

Tresset [83]

Answer:

Step-by-step explanation:

Number of students in soccer club, n(S) = 50

Number of students in Art club, n(A) = 53

Number of students in Gaming club, n(G)

n( $S \cup A\cup G$ ) = 100

n( $S \cap A\cap G$ ) = 9

n( $S \cap A$ ) = 20

n( $A \cap G$ ) = 35

n( $G \cap S$ ) = 29

Formula:

n ( A ∪ B ∪ C ) = n(A) + n(B) + n(C) – n ( A ∩ B ) – n(B ∩ C) – n (A ∩ C) + n( A ∩ B ∩ C )

Putting the values:

100 = 50 + 53 + n(G) - 20 - 35 - 29 + 9

100 = 112 + n(G) - 84

n(G) = 72

Number of students in gaming club only = n(G) - n( $G \cap S$ ) - n( $A \cap G$ ) + n( $S \cap A\cap G$ )

= 72 - 35 - 29 + 9

= <em>17</em>

6 0

3 years ago