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3 years ago

Little sister needs help with a math assignment, I'm tired rn anyone know?

Mathematics

2 answers:

hram777 [196]3 years ago

6 0

If you multiply the 2’s you get a 4 and when u multiply the zeros with it you would have to add a zero to the 0.002. So it would be 0.0004

givi [52]3 years ago

3 0

Answer:

because if you do 0.2 multiplied by 10 you get 2 and 0.002 times 1000 you get 2 X 2.

2 X 2 = 4

now if you divide 4 by 10000 (add 10 and 1000 from above) you get 0.0004

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Use differentials to find an approximate value for <img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B65%7D%20" id="TexFormul

Sveta_85 [38]

: Let y = f(x) = x^1/3
Then dy = 1/3*x^(−2/3) dx
Since f(64) = 4.
We take x = 64 and dx = ∆x = 1
This gives dy = 1/3*(64)^(−2/3)* (1) = 1/48
∴65^(1/3) = f(64 + 1) ≈ f(64) + dy = 4 + 1/48 ≈ 4.021

6 0

4 years ago

Read 2 more answers

The probability that two people have the same birthday in a room of 20 people is about 41.1%. It turns out that

salantis [7]

Answer:

a) Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

b) We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

Step-by-step explanation:

Previous concepts

A Bernoulli trial is "a random experiment with exactly two possible outcomes, "success" and "failure", in which the probability of success is the same every time the experiment is conducted". And this experiment is a particular case of the binomial experiment.

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

Solution to the problem

Part a

Let X the random variable of interest, on this case we know that:

$X \sim Binom(n=20, p=0.411)$

This random variable represent that two people have the same birthday in just one classroom

Part b

We can find first the probability that one or more pairs of people share a birthday in ONE class. And we can do this:

$P(X\geq 1 ) = 1-P(X$

And we can find the individual probability:

$P(X=0) = (20C0) (0.411)^0 (1-0.411)^{20-0}=0.0000253$

And then:

$P(X\geq 1 ) = 1-P(X$

And since we want the probability in the 3 classes we can assume independence and we got:

$P= 0.99997^3 = 0.9992$

So then the probability that one or more pairs of people share a birthday in your three classes is approximately 0.9992

4 0

4 years ago

Use the distributive property to remove the parentheses. 3(6-y)

Burka [1]

Answer:

18-3y.

Step-by-step explanation:

3 x 6 = 18

3 x -1y= -3y.

3 0

2 years ago

Read 2 more answers

If you had $350 and you spent the following

Olin [163]

Answer:

B.) $58

Step-by-step explanation:

350-89-18-27-38-120 = 58

6 0

3 years ago

Read 2 more answers

What is the slope of the line represented by the equation y=x/4-€

sveticcg [70]

Y = x/4 - €

y = (1/4)x - €

y = 0.25x - € comparing to y = mx + c

m = slope = 0.25 or (1/4)

5 0

4 years ago