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2 years ago

Little sister needs help with a math assignment, I'm tired rn anyone know?

Mathematics

2 answers:

hram777 [196]2 years ago

6 0

If you multiply the 2’s you get a 4 and when u multiply the zeros with it you would have to add a zero to the 0.002. So it would be 0.0004

givi [52]2 years ago

3 0

Answer:

because if you do 0.2 multiplied by 10 you get 2 and 0.002 times 1000 you get 2 X 2.

2 X 2 = 4

now if you divide 4 by 10000 (add 10 and 1000 from above) you get 0.0004

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Write a number to represent the quantity.<br> a debt of $300

natka813 [3]

Answer:

A debt means subtracting from the original value so a debt of $300 can be expressed as -300.

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3 years ago

Angles BAE and FAC are straight angles. What angle relationship best describes angles BAC and EAF?Adjacent anglesComplementary a

Natalka [10]

The best angle relationship that describes angles BAC and EAF is supplementary angles

The sum of angle on a straight line is supplementary i.e. they sum up to 180 degrees.

If Angles BAE and FAC are straight angles, it means they are linear pairs and their sum is 180 degrees. Mathematically;

m<BAE + m<FAC = 180degrees

Hence we can conclude that the best angle relationship that describes angles BAC and EAF is supplementary angles

Learn more here: brainly.com/question/22309882

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3 years ago

What the slope of (-15,9) (-10,3)

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The slope is - 3/10

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3 years ago

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3 years ago

Two airplanes are flying in the air at the same height. Airplane A is flying east at 300mi/h and airplane B is flying north at 2

Ipatiy [6.2K]

Answer:

$\frac{dAB}{dt}=340 mil/h$

Step-by-step explanation:

The change of distance over time of the plain A is 300 mi/hour and 200 mi/hour for plane B. O is the point of the airport.

So, the distance from A to O AO = 90 miles and BO = 120 miles.

Now, we have a right triangle here. We can use the Pythagorean theorem, so the distance between the planes will be:

$AB^{2} =AO^{2}+BO^{2}$ (1)

$AB =\sqrt{AO^{2}+BO^{2}}=$

$AB =\sqrt{90^{2}+120^{2}}=150 miles$

If we take the derivative of the equation (1) we could find the change of the distance between planes.

$2AB\frac{dAB}{dt}=2AO\frac{dAO}{dt}+2BO\frac{dBO}{dt}$

$2*150\frac{dAB}{dt}=2*90*300+2*120*200=102000 mil/h$

$\frac{dAB}{dt}=\frac{102000}{150*2}$

Finally,

$\frac{dAB}{dt}=340 mil/h$

I hope it helps you!

6 0

3 years ago