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Firlakuza [10]
2 years ago
13

When parents reproduce, they pass different versions of genes, or _____, for different traits to their ____.

Biology
1 answer:
romanna [79]2 years ago
7 0

Answer:

characters

offsprings.

Explanation:

During meiosis, all various genes are separated. The inherited alleles constitute the genotype of the individual.

The transfer of parental to offspring characteristics is called heredity and the heritable features can be predicted.

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What property makes phospholipids ideal building blocks for cell membranes?
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Answer:

The polarity of the phospholipid makes it ideal for a building block of cell membranes.

Explanation:

There is the tails which are hydrophobic (water fearing) and the heads which are hydrophilic (water loving). These properties of phospholipids allow the tails to go towards eachother and heads to face the water which maintains a solid structure allowing certain materials to pass through.

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Which of the following are true concerning the differences between carbohydrates and lipids.
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What are two sources of organic waste that are produced by aquatic ecosystems?
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The two sources of organic wastes that are produces by aquatic system are Nitrogenous- Ammonia and the decaying remains.
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Which of the following best compares the mass and the volume of a solid?
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Volume is the space that an object occupies. Mass is the amount of matter in a given object.
8 0
2 years ago
Alkaptoneuria is a recessive genetic disorder found among North American populations at a frequency of about 1 in 500,000 births
Dafna11 [192]

Answer:

The correct answer is - 1/41,493

Explanation:

Let assume the frequency of the two possible same allele genotype (dominant and recessive) in an inbred population is p and q. Then the frequency of heterozygotes (H) is denoted as:

2pq + 2pqF.  ( where F is the inbreeding coefficient).

The frequency of the two different hoozygotes in inbred population can be calculated as:

p2 + pqF and q2 + pqF. (Where p and q are the allele frequency of the dominant and recessive phenotype.

Given: Frequency of Alkaptonuria (q 2) = 1:500, 000

=> q = 1/707

p = 706/707 ( Approx values)

solution:

Inbreeding coefficient (F) = 1/64

Therefore,

Frequency of Alkaptonuria in second cousins= q 2 + pqF

= 1/500, 000 + (706/707 x 1/707) x (1/64)

= 1/500, 000 + 1/45, 248

= 1/41,493 (approx)

5 0
3 years ago
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