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Answer:
1/4
Explanation:
Given that the F2 cross produces offspring according to the expected 9:3:3:1 ratio.
YyRr X YyRr:
Let us break the dihybrid cross into individual monohybrid crosses.
Yy X Yy :
Y y
Y YY Yy
y Yy yy
2/4 or 1/2 of the offspring are heterozygous for the trait.
Similarly, in Rr X Rr cross, 1/2 of the offspring are heterozygous for the trait.
Together, 1/2 * 1/2 = 1/4 of F2 plants are expected to be heterozygous for both traits.
Answer:
The proteins will be transported through exocytosis; the carbon dioxide will diffuse through the membrane.
Explanation:
Diffusion is the passive transport of substances down their concentration gradient. The process moves the substances from the region of higher concentration to that of lower concentration. CO2 is a small molecule and does not have any charge. Small, uncharged molecules can diffuse through the lipid bilayer of the cell membrane. Therefore, CO2 can exit a cell by simple diffusion.
On the other hand, proteins are too large to be transported by diffusion across the cell membrane. The proteins are transported by exocytosis. During exocytosis of proteins, membrane-bound vesicles are formed inside the cell. These vesicles carry proteins in them and are called secretory vesicles. The membrane of the vesicles fuse with the cell membrane of cells and transport the proteins outside the cell.
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