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Ierofanga [76]
3 years ago
14

PLZ AWNSER I HAVE 10 MIN TIMER PLZ HELP ME

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0
Both ........................
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Write a reciprocal function with asymptotes x=4 and y=-9.
gayaneshka [121]
Attached the solution and work.

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3 years ago
A company that teaches self-improvement seminars is holding one of its seminars in Lancaster. The company pays a flat fee of $98
alukav5142 [94]

Answer:

Step-by-step explanation:

Let x represent the number of attendees that it will take the company to break even.

The company pays a flat fee of $98 to rent a facility in which to hold each session. Additionally, for every attendee who registers, the company must spend $16 to purchase books and supplies. This means that the total cost that the company would pay for x attendees is

16x + 98

Each attendee will pay $65 for the seminar. This means that the total revenue that the company would generate from x attendees is 65x.

At the break even point,

total cost = total revenue

Therefore,

16x + 90 = 65x

65x - 16x = 98

49x = 98

x = 98/49

x = 2

It will take 2 attendees and the total expenses and revenues is

2 × 65 = $130

4 0
3 years ago
What is 5- (t+3)= -1+2(t-3)
maks197457 [2]

Answer:

Step-by-step explanation:

t=3

7 0
2 years ago
Read 2 more answers
Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we
Ksenya-84 [330]

<u>Part a)</u> Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours  

we know that

x+y \leq20 --------> inequality 1  

6x+10y \geq 75 --------> inequality 2

<u>Part b)</u> Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

x+y \leq20 --------> inequality 1

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 1

6x+10y \geq 75 --------> inequality 2  

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N 2

<u>Part c)</u> Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

x+y \leq20 --------> inequality 1

6x+10y \geq 75 --------> inequality 2

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N  3

Let

A(10,10) ------> see the attached figure N  3

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

<u>Prove algebraically </u>

A(10,10)

substitute the value of x and y in the inequalities

<u>inequality 1</u>

10+10 \leq20

20 \leq20 ------> is ok

<u>inequality 2</u>

6*10+10*10 \geq 75

160 \geq 75 -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0
3 years ago
Convert 5.764764764 to a rational expression
NISA [10]

Answer: 5 and 764 over 999

5764 over 9999

5 and 764 over 99

5 and 999 over 764

Step-by-step explanation:

8 0
3 years ago
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