PLZ AWNSER I HAVE 10 MIN TIMER PLZ HELP ME

Find the volume of the cylinder. Use 3.14 for pie

Rudik [331]

Volume of a cylinder formula is
$v = \pi {r}^{2} \times h$
$v = 3.14 \times {3}^{2} \times 12$

3 0

3 years ago

A=244in2<br> H=<br> B=12.6in<br> (1in=2.54cm)

pshichka [43]

Although there is no picture, I will assume this is a triangle we are talking about since the terms base and height are being used. If that is the case, the height is roughly 38.72in.

To find this, we will use the area of a triangle formula.

1/2bh = a ---> plug in known values.
1/2(12.6)(h) = 244 ---> multiply to simplify
6.3(h) = 244 ----> divide both sides by 6.3
h = 38.73

6 0

3 years ago

Think of a situation when someone would need to make a measurement with extreme precision. Describe the setting, why the measure

makkiz [27]

Answer:

Ok, suppose you want to create a battery that fits exactly in the hole that is already created for an electric device, like a cellphone for example.

If the battery is slightly bigger, it will not enter the socket, and the battery will be a loss in time and resources.

If the battery is slightly smaller, it will move when it is in the socket, so the cell phone will shut down randomly when you move it, then this battery is also a loss in time and resources.

So you need to measure exactly the socket in order to make a battery that fits exactly inside of it with very good precision.

This example can be extended for any electronic piece that you need to fit in a given space (for example in microtechnology, the precision of the measures is must be extreme because working with those things is really expensive and you can not mess up with the dimensions of the pieces)

5 0

2 years ago

sume that the change in daily closing prices for stocks on the New York Stock Exchange is a random variable that is normally dis

Darina [25.2K]

Answer:

0.1131 = 11.31% probability that a randomly selected stock will close up $0.75 or more.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of $0.35 and a standard deviation of $0.33.

This means that $\mu = 0.35, \sigma = 0.33$ .