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Ilya [14]
3 years ago
13

Solve for x: 3(x+6)=21. A)1 B) 5 C)9 D) 13 ​

Mathematics
2 answers:
aleksley [76]3 years ago
8 0

Answer:

\boxed {\boxed {\sf A. \ x=1}}

Step-by-step explanation:

We are given the equation:

3(x+6)=21

We want to solve for x, so we must isolate the variable by performing inverse operations to both sides of the equation.

(x+6) is being multiplied by 3. The inverse of multiplication is division. Divide both sides of the equation by 3.

\frac {3(x+6)}{3}=\frac{21}{3}

(x+6)=\frac{21}{3}

(x+6)=7

Now 6 is being added to x. The inverse operation of addition is subtraction. Subtract 6 from both sides of the equation.

x+6-6=7-6

x=7-6

x=1

We can test our solution by plugging 1 in for x in the original equation.

3(x+6)=21

3(1+6)=21

3(7)=21\\21=21

This checks out (21 is equal to 21) so we know our answer is <u>x=1.</u>

Wewaii [24]3 years ago
3 0

Answer:

<h2>A. X=1</h2>

Step-by-step explanation:

To solve this problem, you have to use the distributive property.

Isolate the x from one side of an equation.

Distributive property:

\sf{A(B+C)=AB+AC}

First, divide by 3 from both sides of an equation.

\dfrac{3(x+6)}{3}=\dfrac{21}{3}

Solve.

21÷3=7

Rewrite the problem down.

x+6=7

Then, subtract by 6 from both sides.

\sf{x+6-6=7-6}

Solve.

7-6=1

\Large\boxed{X=1}

The solution is x=1, which is our answer.

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Give the intervals where f(x) is concave up. (enter your answer using interval notation. if an answer does not exist, enter dn
Kipish [7]
Concave up is U-shaped.
There will be a inflection/critical point f'(x) =0 then a negative slope f'(x) = neg then another inflection/critical point f'(x) =0 at the bottom of the U-shape then a positive slope to last inflection/critical point. The interval for the Concave Up shape is the first and last inflection points.
6 0
3 years ago
What are the solutions to the quadratic equation (5y +6) 2= 24?
boyakko [2]

Answer:

y=-2.18,-0.22

Step-by-step explanation:

We have been given the equation

(5y+6)^2=24

Take square root both sides. When ever we take square root, we include plus minus sign

\sqrt{(5y+6)^2}=\pm\sqrt{24}\\\\5y+6=\pm2\sqrt6

Now, subtract 6 to both sides of the equation

5y=-6\pm2\sqrt6

Divide both sides by 5

y=\frac{1}{5}(-6\pm2\sqrt6)

y=\frac{1}{5}(-6+2\sqrt6),y=\frac{1}{5}(-6-2\sqrt6)

In decimal we have

y=-2.18,-0.22



3 0
3 years ago
A study has indicated that the sample size necessary to estimate the average electricity use by residential customers of a large
Zanzabum

Answer:

\sigma=547.1125

Step-by-step explanation:

-The margin of error is calculated using the formula:

ME=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}\\\\

-We substitute the values, n=900 and ME=30 in the formula to solve for standard deviation:

ME=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}\\\\\\30=1.645\times\frac{\sigma}{\sqrt{900}}\\\\\sigma=\frac{30^2}{1.645}\\\\=547.1125

Hence, the population standard deviation is 547.1125

7 0
3 years ago
A raft and a motorboat simultaneously leave from the same point and move down the river. After 2 hours the motorboat turns aroun
lesya692 [45]

Answer:

2 hours

Step-by-step explanation:

Let x mph be the speed of motorboat in still water and y mph be the speed of current.

A raft and a motorboat simultaneously leave from the same point and move down the river, then speeds down the river are:

        motorboat =  x + y mph

        raft = y mph

In two hours they will cover:

        motorboat = 2(x+y) miles

        raft = 2y miles

After 2 hours the motorboat turns around and starts moving towards the raft (against the current), so its speed is now x - y mph.

Let t be the time they move towards each other. In t hours, they cover

        motorboat = t(x - y) miles

        raft = ty miles

The distance from the starting point to the turning point is the same as the sum of the distances the raft covers and the motorboat covers after turning around, so

2(x+y)=2y+t(x-y)+ty \\ \\2x+2y=2y+tx-ty+ty\\ \\2x=tx\\ \\t=2\ hours

6 0
3 years ago
Y=–6x+2<br> –12x – 2y=–4<br> How many solutions does this linear system have?
DerKrebs [107]

The linear equation y = -6x + 2; -12x - 2y = -4 has no solution

<h3>Linear equation</h3>

y = -6x + 2

-12x - 2y = -4

  • Substitute y = -6x + 2 into (2)

-12x - 2y = -4

-12x - 2(-6x + 2) = -4

-12x + 12x -4 = -4

-12x + 12x = - 4 + 4

0 = 0

  • Solve for x

y = -6x + 2

y - 2 = -6x

x = (y - 2) / -6

  • Substitute into (2)

-12x - 2y = -4

-12(y- 2)/ 6 - 2y = -4

(-12y + 24) / 6 - 2y = -4

-2y + 4 - 2y = 4

0 = 0

Learn more about linear equation:

brainly.com/question/4074386

#SPJ1

3 0
1 year ago
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