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Ilya [14]
3 years ago
13

Solve for x: 3(x+6)=21. A)1 B) 5 C)9 D) 13 ​

Mathematics
2 answers:
aleksley [76]3 years ago
8 0

Answer:

\boxed {\boxed {\sf A. \ x=1}}

Step-by-step explanation:

We are given the equation:

3(x+6)=21

We want to solve for x, so we must isolate the variable by performing inverse operations to both sides of the equation.

(x+6) is being multiplied by 3. The inverse of multiplication is division. Divide both sides of the equation by 3.

\frac {3(x+6)}{3}=\frac{21}{3}

(x+6)=\frac{21}{3}

(x+6)=7

Now 6 is being added to x. The inverse operation of addition is subtraction. Subtract 6 from both sides of the equation.

x+6-6=7-6

x=7-6

x=1

We can test our solution by plugging 1 in for x in the original equation.

3(x+6)=21

3(1+6)=21

3(7)=21\\21=21

This checks out (21 is equal to 21) so we know our answer is <u>x=1.</u>

Wewaii [24]3 years ago
3 0

Answer:

<h2>A. X=1</h2>

Step-by-step explanation:

To solve this problem, you have to use the distributive property.

Isolate the x from one side of an equation.

Distributive property:

\sf{A(B+C)=AB+AC}

First, divide by 3 from both sides of an equation.

\dfrac{3(x+6)}{3}=\dfrac{21}{3}

Solve.

21÷3=7

Rewrite the problem down.

x+6=7

Then, subtract by 6 from both sides.

\sf{x+6-6=7-6}

Solve.

7-6=1

\Large\boxed{X=1}

The solution is x=1, which is our answer.

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Sedbober [7]

Answer:

The area of the shaded figure is:

  • <u>20 units^2</u>

Step-by-step explanation:

To obtain the area of the shaded figure, first, you must calculate this as a rectangle, with the measurements: wide (4 units), and long (6 units):

  • Area of a rectangle = long * wide
  • Area of a rectangle = 6 * 4
  • Area of a rectangle = 24 units^2

How the figure isn't a rectangle, you must subtract the triangle on the top, so, now we calculate the area of that triangle with measurements: wide (4 units), and height (2 units):

  • Area of a triangle = \frac{wide*height}{2}
  • Area of a triangle = \frac{4*2}{2}
  • Area of a triangle =\frac{8}{2}
  • Area of a triangle = 4 units^2

In the end, you subtract the area of the triangle to the area of the rectangle, to obtain the area of the shaded figure:

  • Area of the shaded figure = Area of the rectangle - Area of the triangle
  • Area of the shaded figure = 24 units^2 - 4 units^2
  • <u>Area of the shaded figure = 20 units^2</u>

I use the name "units" because the exercise doesn't say if they are feet, inches, or another, but you can replace this in case you need it.

5 0
3 years ago
The value of 5 is plotted on the number line below plot another point on the number line that is 10 units away from 5
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This should be it. Good luck!

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3 years ago
A random sample of 36 students at a community college showed an average age of 25 years. Assume the ages of all students at the
Pavel [41]

Answer:

98% confidence interval for the average age of all students is [24.302 , 25.698]

Step-by-step explanation:

We are given that a random sample of 36 students at a community college showed an average age of 25 years.

Also, assuming that the ages of all students at the college are normally distributed with a standard deviation of 1.8 years.

So, the pivotal quantity for 98% confidence interval for the average age is given by;

             P.Q. = \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \bar X = sample average age = 25 years

            \sigma = population standard deviation = 1.8 years

            n = sample of students = 36

            \mu = population average age

So, 98% confidence interval for the average age, \mu is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98

P(-2.3263 < \frac{\bar X - \mu}{\frac{\sigma}{\sqrt{n} } } < 2.3263) = 0.98

P( -2.3263 \times {\frac{\sigma}{\sqrt{n} } < {\bar X - \mu} < 2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

P( \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } < \mu < \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ) = 0.98

98% confidence interval for \mu = [ \bar X - 2.3263 \times {\frac{\sigma}{\sqrt{n} } , \bar X +2.3263 \times {\frac{\sigma}{\sqrt{n} } ]

                                                  = [ 25 - 2.3263 \times {\frac{1.8}{\sqrt{36} } , 25 + 2.3263 \times {\frac{1.8}{\sqrt{36} } ]

                                                  = [24.302 , 25.698]

Therefore, 98% confidence interval for the average age of all students at this college is [24.302 , 25.698].

8 0
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Can someone help me with this? It’s unit rates with price. Question: 6 feet of ribbon for $19.20​
lbvjy [14]

Answer:

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Step-by-step explanation:

The answer is,

4.53

8 0
3 years ago
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attashe74 [19]

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