For a function to begin to qualify as differentiable, it would need to be continuous, and to that end you would require that
is such that

Obviously, both limits are 0, so
is indeed continuous at
.
Now, for
to be differentiable everywhere, its derivative
must be continuous over its domain. So take the derivative, noting that we can't really say anything about the endpoints of the given intervals:

and at this time, we don't know what's going on at
, so we omit that case. We want
to be continuous, so we require that

from which it follows that
.
Answer:
.
Step-by-step explanation:
Given:
Kerry and her brother and noticed there is 3/4 of a pint of ice cream in the freezer.
After they eat some ice cream there is 1/3 of a pint left.
Question asked:
How much ice cream did Kerry and her brother eat ?
Solution:
Total ice cream in the freezer = 
Ice cream left = 
<h3>They ate = Total ice cream in the freezer - Ice cream left after they ate</h3>

Thus, Kerry and her brother ate
.
Answer:
16
Step-by-step explanation:
Comment if you want explanation
Answer:
$1,875
Step-by-step explanation:
(if 500 is 80%, divide 1500 by 4 to get 20%)
1500 divided by 4 is 375
375 plus 1500 is 1875