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nataly862011 [7]
3 years ago
8

La manifestación de un huracán, el movimiento de los aerogeneradores cuando el viento alcanza una velocidad de 3 a 4 metros por

segundo; la quema de madera para hacer hervir el agua contenida en un recipiente. Son ejemplos de. (2 ptos.)
Chemistry
1 answer:
Arturiano [62]3 years ago
8 0

Answer:

Ambos son ejemplos de procesos de transformación de la energía.

El ejemplo del aerogenerador transforma la energía cinética traslacional del viento en energía cinética rotacional del aerogenerador y pérdidas debido a la fricción, la cual es en forma de calor.

En cambio, el ejemplo del hervido del agua es el ingreso de calor por la combustión de madera para aumentar su energía interna.

Explanation:

Son ejemplos de procesos de transformación de energía, por el Principio de Conservación de la Energía se sabe que la energía total de un sistema no se crea ni se destruye, solo se conserva.

El ejemplo del aerogenerador transforma la energía cinética traslacional del viento en energía cinética rotacional del aerogenerador y pérdidas debido a la fricción, la cual es en forma de calor.

En cambio, el ejemplo del hervido del agua es el ingreso de calor por la combustión de madera para aumentar su energía interna.

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liberstina [14]
You would use a mass spectrometer
7 0
3 years ago
Read 2 more answers
How many milliliters of a 0.205 M solution of glucose, C6H12O6, are required to obtain 150.1 g of glucose?
jekas [21]

Answer:

4050 mL

Explanation:

Given data:

Mass of glucose = 150.1 g

Molarity of solution = 0.205 M

Volume of solution = ?

Solution:

Molarity  = number of moles of solute / L of solution.

Now we will calculate the moles of sugar first.

Number of moles = mass/ molar mass

Number of moles = 150.1 g/ 180.156 g/mol

Number of moles = 0.83 mol

Now we will determine the volume:

Molarity  = number of moles of solute / L of solution.

0.205 M = 0.83 mol / L of solution.

L of solution = 0.83 mol / 0.205 M

L of solution = 4.05 L

L to mL conversion:

4.05 L × 1000 mL / 1 L = 4050 mL

7 0
4 years ago
How many grams are in 0.35 moles of C2H4? please show dimensional analysis
fredd [130]

Answer:

9.8g

Explanation:

Using periodic table find molar mass of C and H:

C=12.01g/mol

H=1.008g/mol

Molar mass of C2H4=(12.01)2+(1.008)4=28.03g/mol

Using molar mass times moles of the chemical to find the mass in 0.35 moles of c2h4:

28.03 x 0.35=9.8grams

5 0
3 years ago
If the crucible originally weighs 3.715 g and 2. 000 g of hydrate are added to it , what is the weight of the water that is lost
dimulka [17.4K]
For this, you need to know 1) the mass of the hydrate and 2) the mass of the anhydrous salt. Once you have both of these, you will subtract 1) from 2) to find the mass of the water lost.

From the problem, you know that 1) = 2.000 g.

Now you need to find 2). You know that your crucible+anhydrous salt is 5.022 g. To find just the anhydrous salt, subtract the mass of the crucible (3.715 g).

1) = 5.022 g - 3.715 g = 1.307 g

Now you can complete our original task.

Mass H2O = 2) - 1) = 2.000 g - 1.307 g = 0.693 g.


4 0
4 years ago
What are two different types of electron microscopes and how might their ability to observe a specimen he different?
Sunny_sXe [5.5K]

Answer:

transmission EM (TEM) and the scanning EM (SEM)

Explanation:

Electron microscopy (EM) is a technique for obtaining high resolution images of biological and non-biological samples. It is used in biomedical research to examine the detailed structure of tissues, cells, organs and gross cell bodies.

There are two main type of electron microscope

  1. the transmission EM (TEM)
  2. the scanning EM (SEM)
  • Transmission electron microscopes are used to see thin specimens so that electrons can produce a projection image. TEM can be adapted in many ways to conventional (compound) light microscopes.
  • TEM is used for the internalization of cells , the formation of protein molecules, viruses, and organization of molecules in the cytoskeletal filaments. And arrangement of protein molecules in cell membranes.
4 0
3 years ago
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