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dexar [7]
3 years ago
10

An overseas flight leaves New York in the late afternoon and arrives in London 8.50 hours later. The airline distance from New Y

ork to London is about 5.6x103 km, depending to some extent on the flight path followed. What is the average speed of the plane, in kilometers per hour to the correct number of significant digits?
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

v = 658.82 km/h

Explanation:

The distance between New York and London is 5.6\times 10^3\ km

Time taken from New York to London is 8.5 hours

We need to find the average speed of the plane.

Total distance covered divided by the total time taken is equal to the average speed of an object. So,

v=\dfrac{d}{t}\\\\v=\dfrac{5.6\times 10^3\ km}{8.5\ h}\\\\v=658.82\ km/h

So, the average speed of the plane is 658.82 km/h.

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(1) ClO-(aq) + H2O(l) HClO(aq) + OH -(aq) [fast] (2) I -(aq) + HClO(aq) HIO(aq) + Cl -(aq) [slow] (3) OH -(aq) + HIO(aq) H2O(l)
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Answer:

ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)

Explanation:

The reactions are:

(1) ClO⁻(aq) + H₂O(l) → HClO(aq) + OH⁻(aq)    [fast]

(2) I⁻(aq) + HClO(aq) →  HIO(aq) + Cl⁻(aq)  [slow]

(3) OH⁻(aq) + HIO(aq) → H₂O(l) + IO⁻(aq)  [fast]

By adding up the 3 equations we get:

ClO⁻(aq) + <em>H₂O(l)</em> + I⁻(aq) + <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em>  →  <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> + Cl⁻(aq) + <em>H₂O(l)</em> + IO⁻(aq)

And by canceling common terms on both sides, we can get the overall equation:

ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)  

Therefore, the overall equation is ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq).

I hope it helps you!  

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