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dexar [7]
3 years ago
10

An overseas flight leaves New York in the late afternoon and arrives in London 8.50 hours later. The airline distance from New Y

ork to London is about 5.6x103 km, depending to some extent on the flight path followed. What is the average speed of the plane, in kilometers per hour to the correct number of significant digits?
Chemistry
1 answer:
Evgesh-ka [11]3 years ago
4 0

Answer:

v = 658.82 km/h

Explanation:

The distance between New York and London is 5.6\times 10^3\ km

Time taken from New York to London is 8.5 hours

We need to find the average speed of the plane.

Total distance covered divided by the total time taken is equal to the average speed of an object. So,

v=\dfrac{d}{t}\\\\v=\dfrac{5.6\times 10^3\ km}{8.5\ h}\\\\v=658.82\ km/h

So, the average speed of the plane is 658.82 km/h.

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A buffer solution is made that is 0.347 M in H2C2O4 and 0.347 M KHC2O4.
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Answer:

1. pH = 1.23.

2. H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Explanation:

Hello!

1. In this case, for the ionization of H2C2O4, we can write:

H_2C_2O_4\rightleftharpoons HC_2O_4^-+H^+

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pH=1.23+log(\frac{0.347M}{0.347M} )\\\\pH=1.23+0\\\\pH=1.23

2. Now, since the addition of KOH directly consumes 0.070 moles of acid, we can compute the remaining moles as follows:

n_{acid}=0.347mol/L*1.00L=0.347mol\\\\n_{acid}^{remaining}=0.347mol-0.070mol=0.277mol

It means that the acid remains in excess yet more base is yielded due to the effect of the OH ions provided by the KOH; therefore, the undergone chemical reaction is:

H_2C_2O_4(aq) +OH^-(aq)\rightarrow HC_2O_4^-(aq)+H_2O(l)

Which is also shown in net ionic notation.

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