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Leya [2.2K]
3 years ago
12

Hard water often contains dissolved Ca2+ and Mg2+ ions. One way to soften water is to add phosphates. The phosphate ion forms in

soluble precipitates with calcium and magnesium ions, removing them from solution. Suppose that a solution is 0.054 M in calcium chloride and 0.093 M in magnesium nitrate. What mass of sodium phosphate would have to be added to 1.4 L of this solution to completely eliminate the hard water ions? Assume complete reaction. Enter a numerical answer only, in terms of grams to two significant figures.
Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

Explanation:

We will first write the balanced equation for this scenario

3 CaCl2 + 2 Na3PO4 ----> 6 NaCl + Ca3 (PO4)2

3 Mg(NO3)2 + 2 Na3PO4 -----> 6 NaNO3 + Mg3 (PO4)2

The ratio here for both calcium chloride and magnesium nitrate is 3:2

The number of moles of each compound is equal to

0.054 * 1.4 = 0.0756\\0.093* 1.4 = 0.1302

Using the mole ratio of 3:2, convert each to moles of sodium phosphate.

0.0756 mole of CaCl2 is equal to 0.05\\ Na3PO4

0.1302 mole of CaCl2 is equal to 0.0868 Na3PO4

Converting moles of sodium phosphate to grams of sodium phosphate we get

(0.05 +0.0868) * 163.94 g/mol

22.4269 grams of sodium phosphate must be added to 1.4 L of this solution to completely eliminate the hard water ions

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Answer:

Explanation:

Reaction Given

    NaHCO₃ (s) + HC₂H₃O₂ (aq) -------> CO₂ (g) + H₂O (l) + NaC₂H₃O₂ (aq)

Balance Equation = ?

Solution:

Balance Chemical Equation:

A balanced chemical equation is that in which the number of the reactant atoms equal to the number of the product atom.

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Check the chemical equation and count the number of atoms at the reactant side and product side.

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Number of atoms of Product:

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So this a balance equation as the atoms of the reactant atom equal to the number of the product atoms.

Na atom is 1 on both reactant and product side

Oxygen atoms are 5 on reactant and 5 on product side

hydrogen atoms are 5 on reactant and 5 on product side

Carbon atoms are 3 on reactant and 3 on product side

So all the compounds in the reaction have 1 as its coefficient in the blanks

<u />

<u>1   </u>NaHCO₃ (s) +  <u>1  </u>HC₂H₃O₂ (aq) -----> <u>1  </u>CO₂ (g) + <u>1  </u>H₂O (l) + <u>1  Na</u>C₂H₃O₂ (aq)

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