Answer:
Dry ice undergoes sublimation, an endothermic change at room temperature.
Answer:
This question is incomplete
Explanation:
There are two major forms of energy; these are potential and kinetic energy. Kinetic energy is the energy present in moving options. Examples include mechanical and electrical energy.
The formula for kinetic energy is 1/2mv² where "m" is mass and "v" is velocity.
While potential energy is the energy present in stationary objects that can be put to use in future. Example includes a ball in its resting state. The formula for potential energy is "mgh" where "m" is mass, "g" is acceleration due to gravity and "h" is height
Considering the law of conservation of energy which states that energy can neither be created nor destroyed but can be transformed from one form to another. Looking at the example provided earlier for potential energy, a ball in its resting position (having a potential energy) when kicked will have a kinetic energy (which can be calculated with the formula provided earlier), hence
Total energy = potential energy (P.E) + kinetic energy (K.E)
This formula and the explanation above can be used to answer the completed question.
NOTE: There is no standard relationship between P.E and K.E. They could be directly or indirectly proportional depending on the circumstance.
a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp AgBr = s²
c. 5 x 10⁻¹³ mol/L
<h3>Further explanation</h3>
Given
solubility AgBr = 7.07 x 10⁻⁷ mol/L
Required
The dissolution reaction
Ksp
The solubility product constant
Solution
a. dissolution reaction of AgBr
AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)
b. Ksp
Ksp AgBr = [Ag⁺] [Br⁻]
Ksp AgBr = (s) (s)
Ksp AgBr = s²
c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³ mol/L
3.6 x 10^-4
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In order to calculate the final concentration of a dilution, it is important to memorise and remember the following equation:
C1V1/C2V2
Where:
C1 = Initial concentration
V1 = Initial volume
C2 = Final concentration
V2 = Final volume
We are given three of the four, and we are asked to calculate the final concentration in moles, so we may substitute these given values into our equation as follows:
C1V1 = C2V2
(2.00m)(50.0 mL) = (C2)(500mL)
100 = C2(500mL)
C2 = 0.2 m
In the final step, we simply divide 100 by 500 to get our final concentration value.
