Answer:
14. x = 16; y = 23
15. x = 9; y = 13
Step-by-step explanation:
14. (4x + 4) = (7x - 44) (alternate exterior angles are congruent)
4x + 4 = 7x - 44
Collect like terms
4x - 7x = -4 - 44
-3x = -48
Divide both sides by -3
x = -48/-3
x = 16
39° + (8y - 43)° = 180° (consecutive exterior angles are supplementary)
39 + 8y - 43 = 180
Add like terms
-4 + 8y = 180
Add 4 to both sides
8y = 180 + 4
8y = 184
Divide both sides by 8
y = 184/8
y = 23
15. (15x - 26)° = (12x + 1)° (alternate exterior angles are congruent)
15x - 26 = 12x + 1
Collect like terms
15x - 12x = 26 + 1
3x = 27
Divide both sides by 3
x = 27/3
x = 9
28° + (12x + 1)° + (4y - 9)° = 180° (sum of interior angles of ∆)
Plug in the value of x
28 + 12(9) + 1 + 4y - 9 = 180
28 + 108 + 1 + 4y - 9 = 180
Add like terms
128 + 4y = 180
Subtract 128 from each side of the equation
4y = 180 - 128
4y = 52
Divide both sides by 4
y = 52/4
y = 13
Answer:
5/13
Step-by-step explanation:
because we are looking at B and A and c
Answer:
V ( Vcos 60° , Vsin60°) or V ( 2, 2√3)
Step-by-step explanation:
A vector and its components form a right triangle, then we need to get trigonometric functions ( sin and cos) of the angle of the module with x-axis
π/3 = 180⁰/3 = 60⁰ Angle between vector and positive x-axis
and sin 60⁰ = √3 /2 cos 60⁰ = 1/2
Let call V(x) component of vector v in x-axis, and V(y) component of vector v in y-axis then
V(x) = |v|*cos 60⁰ ⇒ V(x) = |v|*1/2 ⇒ V(x) = 4*1/2 ⇒ V(x) = 2
And
V(y) = |v|*sin 60⁰ ⇒ V(y) = |v|*√3/2 ⇒ V(y) = 4*√3/2 V(y) = 2*√3
V = (Vx,Vy) V ( Vcos 60° , Vsin60°) V ( 2, 2√3)
Answer:
1/12 per bag
Step-by-step explanation:
A Fisherman spent his weekend working on his farmland
He had 1/6 of a bag of soil
He spreads it evenly among his 2 garden beds
Therefore the soil in each garden bed can be calculated as follows
= 1/6 ÷ 2
= 1/6 × 1/2
= 1/12 per bag
Answer:
Your Grade Will go up no worries
Step-by-step explanation: