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2 years ago

HELP ME PLEASEEE!!!FIND THE VALUE/ANSWER

Mathematics

2 answers:

kirill115 [55]2 years ago

8 0

It should be 3, -3, -7, 3

enot [183]2 years ago

8 0

Answer:

5-2=3

2-5= -3

-5+(-2)= -7

-2-(-5)= 3

Step-by-step explanation:

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Solve the equation.

Levart [38]

Answer:

x=34

Step-by-step explanation:

6 - ( x-7) ^ 1/3 = 3

Subtract 6 from each side

6-6 - ( x-7) ^ 1/3 = 3-6

- ( x-7) ^ 1/3 = -3

Divide each side by a negative

( x-7) ^ 1/3 = 3

Cube each side

( x-7) ^ 1/3 ^3 = (3)^3

x-7 = 27

Add 7 to each side

x-7+7 = 27+7

x = 34

Check

6 - ( 34-7) ^ 1/3 = 3

6 - (27^1/3 = 3

6 -3 =3

3=3

Good solution

8 0

3 years ago

Jeffrey is biking through the mountains. He bikes for six hours every day. When he started his ride one day the temperature was

Mashcka [7]

Answer:

Step-by-step explanation:

6 0

3 years ago

In a class of 20 students, 40% are boys. 25% of the boys and 50% of the girls wear glasses. How many students wear glasses?

fredd [130]

Calcualate 40% (0.40) times 20 to get that there are 8 boys in the class. The rest must be girls, so 20 - 8 gives you 12 girls. 25% (0.25) times the 8 boys gives you that 2 of the boys wear glasses. 50% (0.5) times the 12 girls tives you that 6 girls wear glasses. Add together the 2 boys and the 6 girls that wear glasses to get that a total of 8 students wear glasses.

3 0

3 years ago

Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$

And the Least Value of the domain is -4.

3 0

2 years ago

Using the Completing the Square method, what are the zeros of the quadratic function f(x) = 2x2 + 8x - 3?

Ipatiy [6.2K]

Answer:

Step-by-step explanation:

1) to rewrite the given equation:

f(x)=2(x²+4x)-3; ⇔ f(x)=2(x²+4x+4)-3-8; ⇔ f(x)=2(x²+4x+4)-11; ⇔ f(x)=2(x+2)²-11;

2) the roots are:

$\left[\begin{array}{ccc}x=-\sqrt{\frac{11}{2}}-2 \\x=\sqrt{\frac{11}{2}}-2 \end{array}$

3) finally, the correct answer is A.

4 0

1 year ago