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ludmilkaskok [199]
3 years ago
11

Write the product in standard form.(2 - 3i)(2 + i)​

Mathematics
2 answers:
Stels [109]3 years ago
8 0

Answer:

Brainelist?

Step-by-step explanation:

7-4i

just use a online calculator

Nata [24]3 years ago
8 0

Answer:

7-4i

Step-by-step explanation:

(2 - 3i)(2 + i)​

FOIL

first 2*2 = 4

Outer: 2i

Inner: -3i*2 = -6i

Last: -3i*i = -3i^2 = -3(-1) = 3

Add them together

4+2i-6i+3

7-4i

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What is the volume of this rectangular pyramid?<br> 6 ft<br> 7 ft<br> 7 ft<br> cubic feet
sasho [114]

98 cubic feet

Step-by-step explanation:

1/3 × 6 × 7 × 7 = 98

Hope this helps!

4 0
2 years ago
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......i need help please..........​
makkiz [27]

Answer:

Step-by-step explanation:

So, TML = 104, right?

Now, we know that TMV + LMV is 104.

We also know that TMV is 60.

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LMV is simply 104 - 60 = 54

LMV = 54 :)

5 0
3 years ago
Read 2 more answers
Find the vertex and length of the latus rectum for the parabola. y=1/6(x-8)^2+6
Ivan

Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

then its vertex is located at the point (h, k). Therefore, the vertex of the parabola

y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

\text{latus rectum} = 4\left(\dfrac{3}{2}\right) = 6

5 0
3 years ago
How can csc^2-cot^2 = 1?
Softa [21]

ANSWER

By simplifying the left hand side using the Pythagorean Identity.

EXPLANATION

The given identity is

\csc^{2} (x) -  \cot^{2} (x) = 1

Take the left hand side and simplify to get the right hand side.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1}{\sin^{2} (x)}  - \frac{ \cos^{2} (x)}{\sin^{2} (x)}

Collect LCM for the denominators.

\csc^{2} (x) -  \cot^{2} (x) =  \frac{1 -  \cos^{2} (x)}{\sin^{2} (x)}

Recall the Pythagorean Identity.

\cos^{2} (x) +  \sin^{2} (x) = 1

This implies that:

1 -  \cos^{2} (x) =  \sin^{2} (x)

We substitute this to get,

\csc^{2} (x) -  \cot^{2} (x) =  \frac{\sin^{2} (x)}{\sin^{2} (x)}

\csc^{2} (x) -  \cot^{2} (x) = 1

6 0
2 years ago
Help:) Factor f(x) = 4x^3+ 23x^2- 70x + 16 into linear factors given that - 8 is a zero of f(x).
Charra [1.4K]

Answer:

(x + 8)(x - 2)(4x - 1)

Step-by-step explanation:

Given that x = - 8 is a zero then (x + 8) is a factor

Divide f(x) by (x + 8) using Synthetic division

- 8 | 4    23    - 70    16

        ↓  - 32      72   - 16

      ---------------------------------

        4    - 9       2       0

Quotient = 4x² - 9x + 2 = (x - 2)(4x - 1)

Thus

f(x) = (x + 8)(x - 2)(4x - 1)

 

8 0
3 years ago
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