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Wewaii [24]
3 years ago
6

What is lossless compression

Computers and Technology
2 answers:
Misha Larkins [42]3 years ago
6 0

Answer:

a class of data compression algorithms that allows the original data to be perfectly reconstructed from the compressed data.

Explanation:

Mazyrski [523]3 years ago
5 0

Answer:

Lossless compression means that as the file size is compressed, the picture quality remains the same - it does not get worse. Also, the file can be decompressed to its original quality.

Explanation:

hope this helps

please brainliest

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(1) Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a
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Answer:Prompt the user to enter two words and a number, storing each into separate variables. Then, output those three values on a single line separated by a space. (Submit for 1 point) Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 Note: User input is not part of the program output. (2) Output two passwords using a combination of the user input. Format the passwords as shown below. (Submit for 2 points, so 3 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 (3) Output the length of each password (the number of characters in the strings). (Submit for 2 points, so 5 points total). Ex: If the input is: yellow Daisy 6 the output after the prompts is: You entered: yellow Daisy 6 First password: yellow_Daisy Second password: 6yellow6 Number of characters in yellow_Daisy: 12 Number of characters in 6yellow6: 8

I have tried several different ways of doing this, but I keep getting an error on line 6

Explanation:

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3 years ago
A program with a graphical user inter-face for displaying HTML files, used to navigate the World Wide Web.
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IP Address or World Wide Web
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2 years ago
The sum of all the minterms of a boolean function of n variables is equal to 1.
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The answers are as follows:

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= (A' + A)(B'C' + B'C + BC' + BC) = B'C' + B'C + BC' + BC

= B'(C' + C) + B(C' + C) = B' + B = 1


b) F(x1, x2, x3, ..., xn) = ∑mi has 2n/2 minterms with x1 and 2n/2 minterms

with x'1, which can be factored and removed as in (a). The remaining 2n1

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with x'2, which and be factored to remove x2 and x'2, continue this

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3 years ago
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text effects, and typography.

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