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Novosadov [1.4K]
2 years ago
6

I cant find the height to the area!!! THE SHAPE IS A TRIANGLE

Mathematics
2 answers:
Igoryamba2 years ago
8 0

Answer:

x = 7.3

Step-by-step explanation:

area = base × height / 2

21.9 = 6 × x / 2

43.8 = 6x

x = 7.3

Vinvika [58]2 years ago
8 0

Answer:

7.3

Step-by-step explanation:

The formula to find the area of a triangle is (1/2)(a)h = A.

Replace the variable h (height) with x.

Isolate the x variable (height) in order to find the height value.

(1/2)(6)x = 21.9

3x = 21.9

x = 21.9/3

x = 7.3

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sveta [45]

Answer:

This means that on the coordinate plane, the coordinates for the vertices of the figure will change. To graph a translation, perform the same change for each point. ... In a reflection, the figure flips across a line to make a mirror image of itself.

Step-by-step explanation:

7 0
3 years ago
A group of 5 students are running a relay race. If the race is 1/4 of a mile long and each student runs the same distance how fa
abruzzese [7]
1/20 mile. divide 1/4 by 5 by fliping the division sign and 5. (1/4)(1/5)=1/20
6 0
3 years ago
Read 2 more answers
Select all the correct answers.
evablogger [386]
Answer:
The 3rd and 4th option

Explanation:
A function only works when the input (x) only has one output (y).
The first, second, and the last option has the input has two or more outputs.

Fun Fact:
It is okay for the outputs to have more then in input, but not okay for the input to have more then one output.

I hope this help and have a nice day :)
6 0
3 years ago
PLLLLLSSSS Heeeellppp ill mark brainliest I promisseeeeeeee plsssss
WARRIOR [948]

Answer:

2\,(x-1)^2=4

which is the first option in the list of possible answers.

Step-by-step explanation:

Recall that the minimum of a parabola generated by a quadratic expression is at the vertex of the parabola, and the formula for the vertex of a quadratic of the general form:

y=ax^2+bx+c

is at   x_{vertex}=\frac{-b}{2\,a}

For our case, where a=2\,\,, b=-4\,\,,\,\,and \,\,c=-2  we have:

x_{vertex}=\frac{-b}{2\,a}\\x_{vertex}=\frac{4}{2\,*\,2}\\x_{vertex}=1

And when x = 1, the value of "y" is:

y(x)=2x^2-4x-2\\y(1)=2(1)^2-4(1)-2\\y(1)=2-6\\y(1)=-4\\y_{vertex}=-4

Recall now that we can write the quadratic in what is called: "vertex form" using the coordinates (x_{vertex},y_{vertex)of the vertex as follows:

y-y_{vertex}=a\,(x-x_{vertex})^2

Then, for our case:

y-(-4)=2\,(x-1)^2\\y=2\,(x-1)^2-4

Then, for the quadratic equal to zero as requested in the problem, we have:

y=2\,(x-1)^2-4=0\\2\,(x-1)^2-4=0\\2\,(x-1)^2=4

5 0
3 years ago
Will mark brainist to the first person who comments!
Galina-37 [17]

Answer:

TRY B

Step-by-step explanation:

TRY B

5 0
3 years ago
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