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2 years ago

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Tickets for a concert cost $10 each if you order them online, but you must pay a service charge of $8 per order. The tickets cos

t $12 each if you buy them at the door on the night of the concert. Write a system of equations to model the situation. (Identify your variables)

1 answer:

klasskru [66]2 years ago

5 0

Answer:

below

Step-by-step explanation:

x: ticket

y: total cost

y= 10x + 8

y= 12x

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Alejandro loves to go to the movies. He goes both at night and during the day. The cost of a matinee is 7 dollars. The cost of a

saw5 [17]

Answer:

<u>Alejandro went to 8 matinee shows and 4 evening shows.</u>

<u>Our system of equations:</u>

<u>x + y = 12</u>

<u>7x + 12y = 104</u>

Correct statement and question:

Alejandro loves to go to the movies. He goes both at night and during the day. The cost of a matinee is 7 dollars. The cost of an evening show is 12 dollars.

Alejandro went to see a total of 12 movies and spent $ 104. How many of each type of movie did he attend? Write a system of equations.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

Step 1:

Let x to represent the number of matinee shows Alejandro went to.

Let y to represent the number of evening shows Alejandro went to.

Now, let's write our system of equations:

x + y = 12

7x + 12y = 104

*********************

x = 12 - y

*********************

7 (12 - y) + 12y = 104

84 - 7y + 12y = 104

5y = 104 - 84

5y = 20

y = 20/5

<u>y = 4 ⇒ x = 12 - 4 = 8</u>

<u>Alejandro went to 8 matinee shows and 4 evening shows.</u>

4 0

3 years ago

The sum of two numbers is 57 The larger number is 15 more than the smaller number. What are the numbers?

mixas84 [53]

X+y=57
y=x+15
x+x+15=57
2x=42
x=21
y=21+15
y=36

5 0

2 years ago

Plss solve 29 for me.with the steps<br> plsssßs I am begging u

lakkis [162]

That means that the first rectangle and the first triangle ave athe same perimiter

so therefor
perimiter=sides added up
rectangle has 4 sides bu 2 is given so double it since the other side is same legnth
rec=x+x+4
multiply 2
2x+2x+8=4x+8=perimiter
this is equal to perimiter of triangle which is
x+9+x+5+x=3x+14
therefor
4x+8=3x+14
subtract 3x from both sides
x+8=14
subtract 8 from both sides
x=6
first one x=6

second rectangle and second triangle
s+7 and 3s
2 sides
2s+14+6s=p
8s+14=p

traignel=2s+12+2s+12+2s+12=6s+36=p
they are equal so
8s+14=6s+36
subtract 6s from both sides
2s+14=36
subtract 14 from both sides
2s=22
divide both sideds by 2
s=11

the values are
pair one:
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pair 2:
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2 years ago

Area of a circle is 80 cm². Work out the circumference of the circle.

GuDViN [60]

Answer:

The circumference of circle is: 31.714 cm

Step-by-step explanation:

Let C be the circumference of the circle

And A be the area of circle

It is given that:

$A = 80cm^2$

We have to find the radius first so that it can be used to find the circumference

The area of circle is given by the formula:

$A = \pi r^2$

Putting the value of area

$80 = 3.14 * r^2\\\frac{80}{3.14} = r^2\\r^2 = 25.477$

Taking square root on both sides

$\sqrt{r^2} = \sqrt{25.477..}\\r = 5.0475\ cm$

Now

$C = 2\pi r$

Putting the value of radius

$C = 2 * 3.14 * 5.05\\C = 31.714\ cm$

Hence,

The circumference of circle is: 31.714 cm

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2 years ago

Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

3 0

3 years ago