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zlopas [31]
3 years ago
9

Find the surface area of a triangular prism

Mathematics
2 answers:
MrRissso [65]3 years ago
8 0
That’s the answer. Dhjahsgs
Elan Coil [88]3 years ago
3 0

\huge\mathrm{Answer࿐}

Surface area of Triangular prism :

  • \mathrm{(2 \times  \dfrac{1}{2}  \times 8 \times 6) + (3 \times 10 \times 20)}

  • \mathrm{48 +600 }

  • 648

Surface area = 648 cm²

_____________________________

\mathrm{ \#TeeNForeveR}

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Maru [420]
486.40*16%= around 77.82 dollars
4 0
2 years ago
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Dinda membeli sebuah handphone seharga Rp2.500,000,00. Setelah 5 bulan, ia menjualnya dengan
Anit [1.1K]

Answer:

Dinda received a 32% loss percentage.

Step-by-step explanation:

<u><em>The question in English is</em></u>

Dinda bought a phone for Rp.2,500,000.00. After 5 months, she sells it with

the price of Rp1,700,000.00. What percentage of losses did Dinda receive?

we know that

Rp.2,500,000.00 represent the 100%

so

Using a proportion

Find out what percentage represent the difference between the original value and the final value

\frac{2,500,000}{100\%}=\frac{2,500,00-1,700,000}{x}\\\\x=100(800,000)/2,500,000\\\\x=32\%

therefore

Dinda received a 32% loss percentage.

6 0
3 years ago
How do u work this problem out
charle [14.2K]
Okay what problem is it that you need help with??
4 0
4 years ago
Robin had 7/8 pound of butter when she started baking a cake. She used 1/4 pound of butter while baking. How much butter was lef
8_murik_8 [283]

Answer:

\dfrac{5}{8} butter was left after she was done baking.

Step-by-step explanation:

Robin had 7/8 pound of butter when she started baking a cake. She used 1/4 pound of butter while baking.

We need to find how much butter was left after she was done baking.

It can be calculated as follows,

Left =

=\dfrac{7}{8}-\dfrac{1}{4}\\\\=\dfrac{7}{8}-\dfrac{2}{8}\\\\=\dfrac{7-2}{8}\\\\=\dfrac{5}{8}

Hence, \dfrac{5}{8} butter was left after she was done baking

3 0
3 years ago
The coordinates of three of the vertices of parallelogram ABCD are A(1, 0), B(2, 3), C(3, 2). What are coordinates of the fourth
nalin [4]

Answer:

 A) The coordinates of the fourth vertex are:

1) x-coordinate:

x=2

2) y-coordinate:

y=-1

B) The point of intersection of the diagonals is:  (2,1)

Step-by-step explanation:

We need to remember that the diagonals of a parallelogram intersect each other at a half-way point and the midpoint of each diagonal is the same.

The midpoint formula is:

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Since:

M_{AC}=M_{BD}

We can find the coordinates of the fourth vertex D(x,y) through these procedure:

1) x-coordinate:

\frac{1+3}{2}=\frac{2+x}{2}\\\\2(2)=x\\\\4-2=x\\\\x=2

2) y-coordinate:

\frac{0+2}{2}=\frac{3+y}{2}\\\\1(2)-3=y\\\\y=-1

Therefore,  fourth vertex is D(2,-1)

Since the point of intersection of the diagonals is the midpoint of a diagonal (Remember that  M_{AC}=M_{BD}), this is:

M_{AC}=M_{BD}=(\frac{1+3}{2},\frac{0+2}{2})\\\\M_{AC}=M_{BD}=(2,1)

Therefore, the point of intersection of the diagonals is (2,1)

7 0
4 years ago
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