Answer: Third option
![u = -\frac{5\sqrt{29}}{29}i -\frac{2\sqrt{29}}{29}j](https://tex.z-dn.net/?f=u%20%3D%20-%5Cfrac%7B5%5Csqrt%7B29%7D%7D%7B29%7Di%20-%5Cfrac%7B2%5Csqrt%7B29%7D%7D%7B29%7Dj)
Step-by-step explanation:
A unit vector
is a vector that has magnitude 1.
To find a unit vector in the direction of the vector v we must first calculate the magnitude of v and then divide the vector v by its magnitude
The vector v is:
v = -5i - 2j
The magnitude of the vector is:
![| v | =\sqrt{(-5)^2 +(-2)^2}\\\\|v|= \sqrt{29}](https://tex.z-dn.net/?f=%7C%20v%20%7C%20%3D%5Csqrt%7B%28-5%29%5E2%20%2B%28-2%29%5E2%7D%5C%5C%5C%5C%7Cv%7C%3D%20%5Csqrt%7B29%7D)
Now we divide the vector v by its magnitude
![u = \frac{1}{\sqrt{29}}v](https://tex.z-dn.net/?f=u%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%7B29%7D%7Dv)
![u = -\frac{5}{\sqrt{29}}i -\frac{2}{\sqrt{29}}j](https://tex.z-dn.net/?f=u%20%3D%20-%5Cfrac%7B5%7D%7B%5Csqrt%7B29%7D%7Di%20-%5Cfrac%7B2%7D%7B%5Csqrt%7B29%7D%7Dj)
Simplifying we have to
![u = -\frac{5\sqrt{29}}{29}i -\frac{2\sqrt{29}}{29}j](https://tex.z-dn.net/?f=u%20%3D%20-%5Cfrac%7B5%5Csqrt%7B29%7D%7D%7B29%7Di%20-%5Cfrac%7B2%5Csqrt%7B29%7D%7D%7B29%7Dj)
Answer:
ask the tutors on brainly they will help with these! ASK A TUTOR BRO
To find this you will use the y2-y1/x2-x1
(-7/2, -3) (-5, 5/2)
x1 y1 x2 y2
5/2 - (-7/2)
_________
-5-(-3)
12/2=6
-2
6/-2= -3
slope= -3
Answer:
84m2
Step-by-step explanation:
it is not b because that is only the area of the square inside of the parallelogram i know that for a FACT sorry i answered late.
In geometry, the definition of a triangle is a two-dimensional closed figure with three sides. Aside from this, it is proven that the sum of the angles of a triangle is 180°. This is a triangle's innate property. Therefore, any closed shape with three sides is a triangle and it follows that the sum of the three angles is equal to 180°.
It is logical therefore, that the first step in proving this is by using the definition of a triangle.