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Anna11 [10]
2 years ago
7

If y is 6 when x is 3 and y varies directly with x, find y when x is 8. 04 16 11

Mathematics
1 answer:
Zarrin [17]2 years ago
4 0

Answer

y = kx

from the info given k=2

hence when x=8 y=16:

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Which ordered pair makes both inequalities true? y < 3x – 1 y > –x + 4 On a coordinate plane, 2 straight lines are shown.
Katen [24]

Answer:

(4,0)

Step-by-step explanation:

we have

y< 3x-1 ----> inequality A

y \geq -x+4 ----> inequality B

we know that

If a ordered pair is a solution of the system of inequalities, then the ordered pair must satisfy both inequalities (makes true both inequalities)

Verify each ordered pair

case 1) (4,0)

<em>Inequality A</em>

0< 3(4)-1

0< 11 ----> is true

<em>Inequality B</em>

0 \geq -(4)+4

0 \geq 0 ----> is true

so

the ordered pair makes both inequalities true

case 2) (1,2)

<em>Inequality A</em>

2< 3(1)-1

2< 2 ----> is not true

so

the ordered pair not makes both inequalities true

case 3) (0,4)

<em>Inequality A</em>

4< 3(0)-1

4< -1 ----> is not true

so

the ordered pair not makes both inequalities true

case 4) (2,1)

<em>Inequality A</em>

1< 3(2)-1

1< 5 ----> is true

<em>Inequality B</em>

1 \geq -(2)+4

1 \geq 2 ----> is not true

so

the ordered pair not makes both inequalities true

5 0
3 years ago
Read 2 more answers
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