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2 years ago

$3.50 for 1/2 pound of cheese whats the cost for 1 pound

Mathematics

1 answer:

jeka57 [31]2 years ago

6 0

Answer:

7 dollars

Step-by-step explanation:

Because 1/2 a pound is half of 1 pound and 3.50 is the value of half that pound, you can add 3.50 to 3.50 to get 7 dollars which is the value for 1 pound

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Lee wants to cut this piece of canvas into two rectangles that are 3x2 and 3x5. He wants the sum of the two small rectangles to

lord [1]

Yes because 3×2= 6 , 3×5= 15, 15 + 6 = 21

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3 years ago

Which equation matches the graph?

Iteru [2.4K]

Answer:

Step-by-step explanation:

intercept is -4 and slope is rise over run which is 3/1 = 3

put into slope intercept form to achieve answer D

7 0

2 years ago

Read 2 more answers

What is the slope of y-4=5/2(x-2)

OLEGan [10]

The answer is 5/2. The equation is already in point slope form. If you recall, the equation for point slope form is y-y1 = m(x-x1) where y1 and x1 are points on the graph, and m is the slope. In the given equation, m is 5/2 so we know it is the slope.
Alternatively, if you are not familiar with the point slope for equation, you can manipulate the equation to the form of y=mx+b where m is the slope and b is the constant. If you solve for y, you get y=5/2x-1 since 5/2 is in the place of m, we know 5/2 is the slope.

6 0

3 years ago

Rewrite the expression as an equivalent ratio of logs using the indicated base.log17(52.875) to base 10.

s2008m [1.1K]

Answer:

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Step-by-step explanation:

Given

$log_{17}(52.875)$

Required

Convert to base 10

To do this, we make use of the following logarithm laws;

$log_ba = \frac{log_{10}a}{log_{10}b}$

In the given parameters;

$a = 52.875$

$b = 17$

Substitute these values in $log_ba = \frac{log_{10}a}{log_{10}b}$

$log_{17}52.875 = \frac{log_{10}52.875}{log_{10}17}$

Represent as a ratio

$log_{17}52.875 = log_{10}52.875 : log_{10}17}$

Hence;

$log_{17}(52.875)$ is represented as $log_{17}52.875 = log_{10}52.875 : log_{10}17}$

7 0

3 years ago

I literally don't know how to figure this out i haven't done this in ages. Help please

Hitman42 [59]

We begin with an unknown initial investment value, which we will call P. This value is what we are solving for.

The amount in the account on January 1st, 2015 before Carol withdraws $1000 is found by the compound interest formula A = P(1+r/n)^(nt) ; where A is the amount in the account after interest, r is the interest rate, t is time (in years), and n is the number of compounding periods per year.

In this problem, the interest compounds annually, so we can simplify the formula to A = P(1+r)^t. We can plug in our values for r and t. r is equal to .025, because that is equal to 2.5%. t is equal to one, so we can just write A = P(1.025).

We then must withdraw 1000 from this amount, and allow it to gain interest for one more year.

The principle in the account at the beginning of 2015 after the withdrawal is equal to 1.025P - 1000. We can plug this into the compound interest formula again, as well as the amount in the account at the beginning of 2016.

23,517.6 = (1.025P - 1000)(1 + .025)^1
23,517.6 = (1.025P - 1000)(1.025)

Divide both sides by 1.025

22,944 = (1.025P - 1000)

Add 1000 to both sides

23,944 = 1.025P

Divide both by 1.025 for the answer

$22,384.39 = P. We now have the value of the initial investment.

8 0

2 years ago