Answer: 5 inches
Step-by-step explanation:
The x's denote the insects measured so the longest insects would be of lengths:
1³/₄ inch, 1³/₄ inch and 1¹/₂ inch.
Adding them together would require converting them to improper fractions first:
7/4, 7/4, 3/2
Pick a denominator that is both denominators' lowest common multiple = 4
Adding them:
Divide the LCM by the denominator of the fraction and multiply the result by the numerator:
= (7 + 7 + 6) / 4
= 20/4
= 5 inches
If Fiona is to divide the first expression by the second one, clearly only the first term of the first expression is divisible. The remaining terms of the fist expression will remain as the remainder. The remainder from the division done by Fiona should be 5x - 3.
Answer:
The answer would be D, 75.
Step-by-step explanation:
Answer:
a) 615
b) 715
c) 344
Step-by-step explanation:
According to the Question,
- Given that, A study conducted by the Center for Population Economics at the University of Chicago studied the birth weights of 732 babies born in New York. The mean weight was 3311 grams with a standard deviation of 860 grams
- Since the distribution is approximately bell-shaped, we can use the normal distribution and calculate the Z scores for each scenario.
Z = (x - mean)/standard deviation
Now,
For x = 4171, Z = (4171 - 3311)/860 = 1
- P(Z < 1) using Z table for areas for the standard normal distribution, you will get 0.8413.
Next, multiply that by the sample size of 732.
- Therefore 732(0.8413) = 615.8316, so approximately 615 will weigh less than 4171
- For part b, use the same method except x is now 1591.
Z = (1581 - 3311)/860 = -2
- P(Z > -2) , using the Z table is 1 - 0.0228 = 0.9772 . Now 732(0.9772) = 715.3104, so approximately 715 will weigh more than 1591.
- For part c, we now need to get two Z scores, one for 3311 and another for 5031.
Z1 = (3311 - 3311)/860 = 0
Z2 = (5031 - 3311)/860= 2
P(0 ≤ Z ≤ 2) = 0.9772 - 0.5000 = 0.4772
approximately 47% fall between 0 and 1 standard deviation, so take 0.47 times 732 ⇒ 732×0.47 = 344.
