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sergeinik [125]
2 years ago
15

Find the surface are of the regular pyramid

Mathematics
2 answers:
harina [27]2 years ago
6 0

Answer:

146 ft^{2}

Step-by-step explanation:

9x6/2 = 27

27x4 = 108

6x6 = 36

36+108 = 146

nataly862011 [7]2 years ago
4 0
TRUE answer: 144 square feet
So one the triangle face of the pyramid has an area of 27 square feet ( 9 x 6/ 2)

Multiply that by 4 because there are 4 faces of triangles (27 x 4 = 108 square feet)

The area of the square base is 36, we get that by multiplying 6 by 6 (since the square has equal sides.

Add 108 and 36 then you get 144 square feet

MARK BRAINIEST
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(4,3,2)

Step-by-step explanation:

We can solve this via matrices, so the equations given can be written in matrix form as:

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\left[\begin{array}{cccc}1&-4&-1&-10\\2&1&2&15\\3&2&1&20\end{array}\right]

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\left[\begin{array}{cccc}1&-4&-1&-10\\0&9&4&35\\0&14&4&50\end{array}\right]

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\left[\begin{array}{cccc}1&-4&-1&-10\\0&1&\frac{4}{9}&\frac{35}{9}\\0&14&4&50\end{array}\right]


4R2+R1=R1 , -14R2+R3=R3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&-\frac{20}{9}&-\frac{40}{9}\end{array}\right]


-\frac{9}{20}R_3=R_3

\left[\begin{array}{cccc}1&0&\frac{7}{9}&\frac{50}{9}\\0&1&\frac{4}{9}&\frac{35}{9}\\0&0&1&2\end{array}\right]


-\frac{4}{9}R_3+R_2=R2 , -\frac{7}{9}R_3+R_1=R_1


\left[\begin{array}{cccc}1&0&0&4\\0&1&0&3\\0&0&1&2\end{array}\right]


Therefore the solution to the system of equations are (x,y,z) = (4,3,2)

Note: If answer choices are given, plug them in and see if you get what is "equal to".  Meaning plug in 4 for x, 3 for y and 2 for z in the first equation and you should get 20, second equation -10 and third 15.

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