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sergeinik [125]

2 years ago

15

Find the surface are of the regular pyramid

2 answers:

harina [27]2 years ago

6 0

Answer:

146 $ft^{2}$

Step-by-step explanation:

9x6/2 = 27

27x4 = 108

6x6 = 36

36+108 = 146

nataly862011 [7]2 years ago

4 0

TRUE answer: 144 square feet
So one the triangle face of the pyramid has an area of 27 square feet ( 9 x 6/ 2)

Multiply that by 4 because there are 4 faces of triangles (27 x 4 = 108 square feet)

The area of the square base is 36, we get that by multiplying 6 by 6 (since the square has equal sides.

Add 108 and 36 then you get 144 square feet

MARK BRAINIEST

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dalvyx [7]

Answer:

The measure of the side $QR$ is 8.8.

Step-by-step explanation:

Since $LMNO \sim PQRS$ , then $SP \propto OL$ , $RS \propto ON$ , $RQ \propto MN$ and $QP \propto LM$ . From figure we have the following relationship:

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