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3 years ago

Identify the terms, coefficients, and constants in the expression.

Mathematics

1 answer:

valina [46]3 years ago

7 0

Step-by-step explanation:

7 is the coeffiecient

3 is the constant

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

alexandr1967 [171]

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: $2(-4y-9)+5y=-6$

Step-by-step explanation:

We will solve the initial steps for substitution method for finding the correct answer

Given equations are:

$x+4y = -9\ \ \ \ Eqn1\\2x+5y=-6\ \ \ Eqn2$

From equation one

$x+4y = -9\\x+4y-4y = -9-4y\\x = -4y-9$

Putting x = -4y-9 in equation 2

$2(-4y-9)+5y=-6$

Hence,

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: $2(-4y-9)+5y=-6$

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

if the unit selling price is $2.50 and the unit cost is $1 what is the action needed to maintain the gross margin percentage whe

Nikolay [14]

The profit is originally 250% to maintain this you need to multiply the new unit cost by 2.5.
New unit cost $1.25. * 2.5 = $3.12.5

5 0

3 years ago

Defina qué es el producto de un vector por un escalar

Ostrovityanka [42]

Answer: c

Step-by-step explanation:

5 0

2 years ago

What is x and y 2x-3y=-1,y=x-1?

kenny6666 [7]

Answer:

Step-by-step explanation:

2x-3x[x-1]

=2x-3x+1

=-x+1

7 0

2 years ago

Elisa ran a total of 8 4/5 miles on Saturday and Sunday. If she ran 5 1/4 miles on Saturday, how many miles did she run on Sunda

stepladder [879]

Answer: $3\dfrac{11}{20}\ \text{miles}$

Step-by-step explanation:

Given

Elisa run a total of $8\frac{4}{5}$ miles on Saturday and Sunday.

If she runs $5\frac{1}{4}$ miles on Saturday

Then, distance traveled on Sunday is given by

$\Rightarrow 8\dfrac{4}{5}-5\dfrac{1}{4}\\\\\Rightarrow \dfrac{44}{5}-\dfrac{21}{4}\\\\\Rightarrow \dfrac{44\times 4}{5\times 4}-\dfrac{21\times 5}{4\times 5}\\\\\Rightarrow \dfrac{71}{20}\\\\\Rightarrow 3\dfrac{11}{20}\ \text{miles}$

6 0

2 years ago