All categories

2 years ago

What kind of symmetry does this figure have?

Mathematics

1 answer:

salantis [7]2 years ago

7 0

Answer:

Both line and point

I'm sorry if it's wrong

You might be interested in

Which of the following sets of numbers could represent the three sides of a triangle?

san4es73 [151]

Answer:

To enable a set of three numbers to represent three sides of a triangle, sum of smaller two numbers must be greater than the largest number. Hence, only C can represent a triangle.

⚪ The sum of the measures of the interior angles of a triangle in Euclidean space is always 180 degrees

<em><u>The answer is none</u></em>

8 0

2 years ago

What is a simple way to tell that −314 is not the slope of this graph?

MA_775_DIABLO [31]

Answer:

the slope should be going from top left to bottom right not bottom left to top right

7 0

2 years ago

A box of colored crayons contains 11 distinct colors. In how many ways can 2 colors be chosen, assuming that the order of the co

Oduvanchick [21]

Answer:

Step-by-step explanation:

The first crayon is chosen out of 11,so there are 11 choices

The second crayon is chosen out of 10 crayons left so there are 10 choices

11*10 = 110

But we do not care about the order, so we divide by 2 since there are 2 places

110/2 =55

5 0

2 years ago

Read 2 more answers

37. Socks. In your sock drawer you have 4 blue socks, 5 grey socks, and 3 black ones. Half asleep one morning, you grab 2 socks

mihalych1998 [28]

Answer:

a) $\frac{1}{22}$

b) $\frac{7}{22}$

c) $\frac{5}{11}$

d) $\frac{35}{66}$

Step-by-step explanation:

Given,

Number of blue socks = 4,

Grey socks = 5,

Black socks = 3,

Total socks = 4 + 5 + 3 = 12,

Ways of choosing any 2 socks = $^{12}C_2$

$=\frac{12!}{2!10!}$

$=\frac{12\times 11}{2}$

$=6\times 11$

= 66,

a) Ways of choosing 2 blue socks = $^3C_2$

= 3,

Since, $\text{Probability}=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}$

Thus, the probability of selecting 2 blue socks = $\frac{3}{66}=\frac{1}{22}$

b) Ways of choosing 2 shocks, non of them are grey socks = $^7C_2$

$=\frac{7!}{2!5!}$

$=7\times 3$

$=21$

Thus, the probability of selecting no grey socks = $\frac{21}{66}$

$=\frac{7}{22}$

c) ways of selecting atleast 1 black sock = ways of selecting 1 black sock + ways of selecting 2 black socks

$=^3C_1\times ^9C_1+^3C_2$

$=3\times 9 + 3$

$=27 + 3$

= 30,

Thus, the probability of selecting at least 1 black sock = $\frac{30}{66}$

$=\frac{5}{11}$

d) Ways of selecting a green sock = $^5C_1\times ^7C_1$

= 35,

Thus, the probability of selecting a green sock = $\frac{35}{66}$

3 0

3 years ago

Consider the following polynomial expression: 4x^5-16x^2+13x^8. Part A: Write the polynomial expression in standard form.

zavuch27 [327]

Answer:

13x^8 + 4x^5 - 16x^2

Step-by-step explanation:

Standard form is just rearranging each group of numbers so that the group with the most exponents on the variables is at the beginning. So it's basically least to greatest but with exponents. Hope this helped!

7 0

3 years ago