Answer:
![\angle A \cong \angle D](https://tex.z-dn.net/?f=%20%5Cangle%20A%20%5Ccong%20%5Cangle%20D%20)
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that
and also
.
In order to prove that ∆ABC
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
![\angle A \cong \angle D](https://tex.z-dn.net/?f=%20%5Cangle%20A%20%5Ccong%20%5Cangle%20D%20)
Answer:
160 well it was 155 but u round up to 160
Step-by-step explanation:
Answer:
i dont know
Step-by-step explanation:
M is dependent and h is independent
m=money and h=hours, p =money per hour
m=ph
Answer:
-4x^2 -3x - 5
Step-by-step explanation:
-4x^2 + 2x - 5(1 + x)
Distribute
-4x^2 + 2x - 5 -5x
Combine like terms
-4x^2 -3x - 5