I'm going to assume that the room is a rectangle.
The area of a rectangle is A = lw, where l=length of the rectangle and w=width of the rectangle.
You're given that the length, l = (x+5)ft and the width, w = (x+4)ft. You're also told that the area, A = 600 sq. ft. Plug these values into the equation for the area of a rectangle and FOIL to multiply the two factors:

Now subtract 600 from both sides to get a quadratic equation that's equal to zero. That way you can factor the quadratic to find the roots/solutions of your equation. One of the solutions is the value of x that you would use to find the dimensions of the room:

Now you know that x could be -29 or 20. For dimensions, the value of x must give you a positive value for length and width. That means x can only be 20. Plugging x=20 into your equations for the length and width, you get:
Length = x + 5 = 20 + 5 = 25 ft.
Width = x + 4 = 20 + 4 = 24 ft.
The dimensions of your room are 25ft (length) by 24ft (width).
Answer:
B. Square root
Step-by-step explanation:
using distance formula:
x = √z^2 - y^2
y = √z^2 - x^2
=> z = √x^2 + y^2
Larger I think, sorry if that’s wrong.
Answer: 1:52 PM
Step-by-step explanation:
PAULA: 2:14PM FINISHED THE RACE
BEATRICE: FINISHED 22 MINUTES EARLIER THEN PAULA
YOU TAKE 2:14PM AND SUBTRACT THE 22 MINS BEATRICE RAN TO GET YOU ANSWER.
SO 2:14 -14 MINS=2:00PM 14+8=22 (THE MINS BETRICE FINISHED)
2:00-8 MINS ( REMAINING FROM THE 22 ) THEN 2:00-8 MINS =1:52
ANSWER:1:52PM