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3 years ago

If two rectangles have the same perimeter, do they have to be congruent??

2 answers:

5 0

Two rectangles with the same perimeter but may not be congruent, because the length and width dimensions of each may be different.

madreJ [45]3 years ago

4 0

Answer:

No they do not have to be congruent.

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Help me plzzzzzzzzzz

marin [14]

Answer:

what is it?

Step-by-step explanation:

simply,subtract,find the domain,factor,

or write it in standard form.

3 0

3 years ago

Read 2 more answers

Please help!

Sindrei [870]

Answer:

D. Subtraction property of equality

B. 6.5

Step-by-step explanation:

First blank:

The equation is x + 6.5 = 13.

To solve the equation, you want x alone on the left side, showing "x = some number." Since 6.5 is being added to x, you need to SUBTRACT 6.5. You must do the same operation to both sides of an equation, so you need to SUBTRACT 6.5 from both sides of the equation. What allows you to subtract the same number from both sides of an equation is the

<em>D. Subtraction property of equality </em>

Second blank:

Subtract 6.5 from both sides.

x + 6.5 = 13

x + 6.5 - 6.5 = 13 - 6.5

x = 6.5

<em>Answer: B. 6.5</em>

4 0

3 years ago

Which of the following descriptions could represent the Venn diagram?

Setler [38]

Answer:

Step-by-step explanation:

it will be c

8 0

3 years ago

Exercise 12.1.2: The probability of an event under the uniform distribution - random permutations. About A class with n kids lin

Nataly [62]

Answer:

a) $P_a=\frac{1}{n}$

b) $P_b=\frac{1}{n(1-n)}$

c) $P_c=\frac{2}{n}$

Step-by-step explanation:

The question is incomplete:

<em>(a) What is the probability that Celia is first in line? (b) What is the probability that Celia is first in line and Felicity is last in line? (c) What is the probability that Celia and Felicity are next to each other in the line?</em>

a) The probability that Celia is first in line, if there are n kids and all of them have the same chance, is 1/n.

$P_a=\frac{1}{n}$

b) The probability that Celia is first in line and Felicity is last in line is

$P_b=\frac{1}{n} \frac{1}{n-1} =\frac{1}{n(1-n)}$ .

It is deducted like that:

If Celia is placed in the first line (what has a probablity of 1/n), there are left (n-1) kids. Then, the probability of placing Felicity in the last place is 1/(n-1).

Both probabilities multiplied give 1/(n*(n-1)).

c) The probability that Celia and Felicity are next to each other in the line is

$P_c=\frac{2(n-1)!}{n!}=\frac{2}{n}$

There are n! combinations for kids lines, where (n-1)! permutations have Celia before Felicity and other (n-1)! permutations have Felicity before Celia.

Then, we have 2(n-1)! permutations that have Celia and Felicity next to each other, over n! permutations possible.

5 0

3 years ago

a jar contains 6 red jelly beans, 6 green beans, and 6 blue jelly beans if we choose a jelly bean, then another jelly bean witho

seropon [69]

<h3>Answer: 5/51</h3>

======================================================

Explanation:

We have 6 green out of 6+6+6 = 18 total

The probability of getting green is 6/18 = 1/3.

After selecting that green jelly bean and not putting it back, we have 6-1 = 5 green out of 18-1 = 17 total.

The probability of selecting another green is 5/17.

Multiply the two fractions 1/3 and 5/17

(1/3)*(5/17) = (1*5)/(3*17) = 5/51

The probability of selecting two greens in a row is 5/51 where we do not put the first selection back. We also do not replace the green jelly bean with some other identical copy.

Note: 5/51 = 0.098039 approximately

8 0

3 years ago

If two rectangles have the same perimeter, do they have to be congruent??​

If two rectangles have the same perimeter, do they have to be congruent??