Answer:

Step-by-step explanation:
The above question is in the form of an exponential decay. The equation for an exponential decay is given by:

where y and x are variables, b < 1, a is the initial value of y (that is the value of y when x = 0).
Let y represent the number of trees left and x represent the number of months. Given that there is currently 2.5 billion trees, therefore a = 2.5 * 10⁹, b = 0.5% = 0.005. The equations becomes:

It's would be plus haft that number (it's a negative) and the next number would be 0
Answer:
a number line that goes from 0 to 16. the whiskers range from 1 to 12, and the box ranges from 3 to 9. a line divides the box at 7.
Answer:
3.84% of months would have a maximum temperature of 34 degrees or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What percentage of months would have a maximum temperature of 34 degrees or higher?
This is 1 subtracted by the pvalue of Z when X = 34. So



has a pvalue of 0.9616
1 - 0.9616 = 0.0384
3.84% of months would have a maximum temperature of 34 degrees or higher
-3/8 = -0.375
-5/8 = -0.625
-1/8 = -0.125
1/4 = 0.25
<span>0.5 = 0.5
</span>
Therefore 1/4 & 0.5 & -1/8 > -3/8