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3 years ago

BRAINLEST IF CORRECT

Mathematics

1 answer:

DedPeter [7]3 years ago

6 0

Answer:

422.39

Step-by-step explanation:

$A = \pi r^2\\A = 144\pi \\\\144\pi -30 = 422.39$

use a calculator for the above and round

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Lin wants to know how many games teenagers in the United States have on their phones.

Dafna1 [17]

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3 years ago

Help ASAP pleaseee!

natulia [17]

Answer:

Step-by-step explanation:

The probability of getting a 6 is 1/6.

The probability of not getting a 6 is 5/6

We roll a die 4 times and want 2 sixes, and 2 not sixes.

i.e.exact 2 6's

We want a combination of 2 sixes from 4 rolls, so we can use the binomial formula to solve this

(4C2)(1/6)²(5/6)² = 6(1/36)(25/36) = (1/6)(25/36) = 25/216 = 0.1157

Nearest tenth of percent is 0.1157×100=11.6%

Ans :11.6%

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3 years ago

How would you write the expression the product 18 and a number b?

mina [271]

Subtraction: 18 - b
Addition: 18 + b
Multiplication: 18b, or 18 x b
Division: 18 divided (My keyboard doesn't have a division sign?) by b
Hope this helped.

6 0

3 years ago

A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro

kati45 [8]

Answer:

$6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

Step-by-step explanation:

Probability that the car encounters a green light on the first day: $50 \% = 0.5$ .

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

$(0.5) \times 0.5 = 0.25$ .

Condition is met on the first two days and green light on the third day: $(0.5 \times 0.5) \times 0.5 = 0.125$ .
Condition is met on the first three days and green light on the fourth day: $(0.5 \times 0.5 \times 0.5) \times 0.5$ .

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be $(0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1$ .

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. $(0.5^{4} \times 0.1) \times 0.4$

Seventh day: $(0.5^{4} \times 0.1 \times 0.4 ) \times 0.4$
Eighth day: $(0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4$
Ninth day: $(0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4$
Tenth day: $(0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}$

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: $0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%$ .

6 0

3 years ago

Read 2 more answers

Only answer if you're very good at Math.

Simora [160]

Answer:

Solution given:

<u>B: 9x - 4/x^2 - 4</u>

Step-by-step explanation:

5 0

3 years ago