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2 years ago

Someone help plz make sure it’s right plz will mark brainiest

Mathematics

2 answers:

r-ruslan [8.4K]2 years ago

7 0

Answer:

Your answer is B, or the second one from the left

bearhunter [10]2 years ago

5 0

Answer: It would be the 2nd choice

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Answer question bellow!!!

Elina [12.6K]

The answer to your question is false

3 0

2 years ago

What is 90 words in 2 minutes as a unit rate

Gemiola [76]

Answer:

Levi saved 3/5 of the amount he needs to buy a 75 dollar video game. he earns 7.50 per hour working at the pizza shopping town how many hours will he need to work to pay for the rest of the game show all of your work to solve this problem explain the Steps you used! thank you 6th grade form please

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Help! Prove the equality arccos √(2/3) - arccos (1+√6)/(2*√3) = π/6

stealth61 [152]

Answer:

Proof in the explanation

Step-by-step explanation:

Trigonometric Equalities

Those are expressions involving trigonometric functions which must be proven, generally working on only one side of the equality

For this particular equality, we'll use the following equation

$\displaystyle cos(x-y)=cos\ x\ cos\ y+sin\ x\ sin\ y$

The equality we want to prove is

$\displaystyle arccos\ \sqrt{\frac{2}{3}}-arccos\left(\frac{1+\sqrt{6}}{2\sqrt{3}}\right)=\frac{\pi}{6}$

Let's set the following variables:

$\displaystyle x=arccos\ \sqrt{\frac{2}{3}},\ y=arccos(\frac{1+\sqrt{6}}{2\sqrt{3}})$

And modify the first variable:

$\displaystyle x=arccos\ \frac{\sqrt{6}}{3}}=>\ cos\ x= \frac{\sqrt{6}}{3}}$

Now with the second variable

$\displaystyle y=arccos\ \frac{1+\sqrt{6}}{2\sqrt{3}}=>cos\ y=\frac{1+\sqrt{6}}{2\sqrt{3}}=\frac{\sqrt{3}+3\sqrt{2}}{6}$

Knowing that

$sin^2x+cos^2x=1$

We compute the other two trigonometric functions of X and Y

$\displaystyle sin \ x=\sqrt{1-cos^2\ x}=\sqrt{1-(\frac{\sqrt{6}}{3})^2}=\sqrt{1-\frac{6}{9}}=\frac{\sqrt{3}}{3}$

$\displaystyle sin\ y=\sqrt{1-cos^2y}=\sqrt{1-\frac{(\sqrt{3}+3\sqrt{2})^2}{36}}}$

$\displaystyle sin\ y=\sqrt{\frac{36-(3+6\sqrt{6}+18)}{36}}=\sqrt{\frac{15-6\sqrt{6}}{36}}$

Computing

$15-6\sqrt{6}=(3-\sqrt{6})^2$

Then

$\displaystyle sin\ y=\frac{3-\sqrt{6}}{6}$

Now we replace all in the first equality:

$\displaystyle cos(x-y)=\frac{\sqrt{6}}{3}.\frac{\sqrt{3}+3\sqrt{2}}{6}+\frac{\sqrt{3}}{3}.\frac{3-\sqrt{6}}{6}$

$\displaystyle cos(x-y)=\frac{3\sqrt{2}+6\sqrt{3}}{18}+\frac{3\sqrt{3}-3\sqrt{2}}{18}$

$\displaystyle cos(x-y)=\frac{9\sqrt{3}}{18}=\frac{\sqrt{3}}{2}=cos\ \pi/6$

Thus, proven

5 0

3 years ago

Fiona bought some socks that cost $4.95 for each pair

RideAnS [48]

Answer:

4.95a + 6.55b = 27.95

Step-by-step explanation:

Just install variables by the numbers.

6 0

3 years ago

Raymond works in an electronics store and gets a 12 percent employee discount. The original cost of a video game system is $175.

slava [35]

Answer:

A. $154.00

Step-by-Step Explanation:

Okay so, the first step is to get 12% and move the decimal to the left twice like this:

.12

Then, multiply 175 by .12 like this:

175 * .12 = 21

Lastly, subtract 21 from 175 like this:

175 - 21 = $154

6 0

2 years ago

Read 2 more answers