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lapo4ka [179]
3 years ago
7

Using the following intervals for the scores on a 30-point quiz, how many x's would fall over the interval of 19-21 on a line pl

ot?
Scores: 21, 27, 20, 29, 23, 21, 21, 27, 26, 25

Intervals: 19-21, 22-24, 25-27, and 28-30

A.1

B.4
Mathematics
1 answer:
VikaD [51]3 years ago
7 0

Answer:

B. 4

Step-by-step explanation:

Interval: 19-21

Scores that are between 19 and 21 are underlined:

Scores in order: <u>20, 21, 21, 21</u>, 23, 25, 26, 27, 27, 29

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ok what about this.. i'm sorry i just can't think straight at the moment i have too much going on.. 2(-10)-9y=-38 find the value
Natasha2012 [34]

2 (-10) -9y = -38

-20 - 9y = -38

-9y = -38 + 20

-9y = -18

y = -18/-9

y = 2

The value of y is 2

4 0
3 years ago
What is 4(-2) - 2y =8?
vladimir1956 [14]

Answer:

y=-8

Step-by-step explanation:

Remember PEMDAS (Parentheses/Exponents/Multiplication/Division/Adding/Subtracting)

Multiply 4 and -2= -8

-8-2y=8

Now do inverse operations

to get rid of the -8 you add it to the other side = -2y=16

Then to get rid of the -2 you divide it out to get the y by it self to get y=-8

7 0
3 years ago
Read 2 more answers
Which of the following statements best describes the relationship between the point (5,-20) and the system of
Andreyy89

Answer: The point (5,-20) only satisfies the second inequality statement in the system of inequalities shown.

Step-by-step explanation:

It isn't super clear exactly what you're asking, but the first thing we can do is see if the point (5, -20) satisfies the system of equations.

So, we start by plugging in -20 for y and 5 for x.

y > -2x-3

-20 > (-2)(5) - 3

-20 > -10-3

-20 > -13. - we can see that the coordinates DO NOT satisfy the first inequality, now we can try the second equation.

y ≤ 3x + 2

-20 ≤ 3(5) + 2

-20 ≤ 15 +2

-20 ≤ 17 - this inequality is true because -20 is indeed less than 17.

5 0
3 years ago
PLS HELP ME I REALLY NEED HELP
baherus [9]

Answer:

I can't see anything. There is nothing on your screen.

7 0
2 years ago
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Two samples each of size 25 are taken from independent populations assumed to be normally distributed with equal variances. the
NeTakaya

n_1=25, n_2=25\\ \bar{X_1}=35.5, \bar{X_2}=33\\ s_1=3, s_2=4

Pooled Combined Variance s_p=12.5

Test Statistic:

t=\frac{\left(\bar{X_1}-\bar{X_2}\right)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

t=\frac{\left(35.5-33\right)}{12.5\sqrt{\frac{1}{25}+\frac{1}{25}}}

\left|t\right|=0.01414

Degrees of freedom = n_1+n_2-2=25+25-2=48

\alpha =0.05

t-Critical =t_{\alpha /2, n_1+n_2-2}=t_{0.025, 48}=-2.0206 \\Table value=|t|=2.0206\\|t|=2.0206

The table value is greater than the calculated value.

Thus we accept H0.

8 0
3 years ago
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