Ask question

Ask question

All categories

3 years ago

11

What is the value of x

1 answer:

VashaNatasha [74]3 years ago

5 0

Answer:

x = 40

Step-by-step explanation:

According to the Supplementary Angles Theorem, set <em>4x</em><em> </em><em>-</em><em> </em><em>20</em><em> </em>and <em>x</em><em> </em>equal to 180. Once done, combine like-terms to get <em>5x</em><em> </em><em>-</em><em> </em><em>20</em><em> </em><em>=</em><em> </em><em>180.</em><em> </em>So, straight off the bat, we know that <em>5x</em> has to equal 200 [bringing 20 over to the right side of the equivalence symbol], therefore 40 is equal to <em>x</em><em>.</em>

I am joyous to assist you anytime.

You might be interested in

(x+1)(x+8)=<br><br><br> can somebody help me on this

goblinko [34]

X^2+8x+x+8 simplifies to x^2+9x+8

8 0

3 years ago

What is the lateral area of the rectangular prism? Assume the prism is resting on its base. A. 135 in2 B. 270 in2 C. 300 in2 D.

Olegator [25]

You have the length of the sides? If not: a and b is the length of the scratch, h is the height <span>This lateral surface area = 2ah+2bh=2h(a+b)</span>

8 0

3 years ago

There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Find the numbers.

Pani-rosa [81]

There are two numbers whose sum is 64. The larger number subtracted from 4 times the smaller number gives 31. Then the numbers are 45 and 19

<h3><u>Solution:</u></h3>

Given that, There are two numbers whose sum is 64.

Let the number be a and b in which a is bigger.

Then, a + b = 64 ------ eqn (1)

The larger number subtracted from 4 times the smaller number gives 31.

4 x b – a = 31

4b – a = 31 ----- eqn (2)

We have to find the numbers.

So, from eqn (2)

a = 4b – 31

Subatitute a in (1)

4b – 31 + b = 64

On solving we get

5b = 64 + 31

5b = 95

b = 19

So, b = 19, then eqn 1

a + 19 = 64

On simplification,

a = 64 – 19

a = 45

Hence, the two numbers are 45 and 19

3 0

3 years ago

The 1992 world speed record for a bicycle (human-powered vehicle) was set by Chris Huber. His time through the measured 200 m st

Reil [10]

Answer:

a) 30.726m/s and b) 5.5549s

Step-by-step explanation:

a.) What was Chris Huber’s speed in meters per second(m/s)?

Given the distance and time, the formula to obtain the speed is

$v=\frac{d}{t}$ .

Applying this to our problem we have that

$v=\frac{200m}{6.509s}= 30.726m/s$ .

So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.

b) What was Whittingham’s time through the 200 m?

In a) we stated that $v=\frac{d}{t}$ . This formula implies that

$t=\frac{d}{v}$ .

First, observer that $19\frac{km}{h} =19,000\frac{m}{h}=\frac{19,000}{3,600}m/s= 5.2777m/s$ .

Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So, $v=30.726\frac{m}{s} +5.2777\frac{m}{s}= 36.003 m/s.$

Then, applying 1) we have that

$t=\frac{200m}{36.003m/s}=5.5549s.$

So, Sam Whittingham’s time through the 200 m was 5.5549s.

5 0

3 years ago

What is the slope of the line 8x + 6y = 12?

anyanavicka [17]

The slope of the line is -4/3

8 0

3 years ago

Read 2 more answers