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Virty [35]
3 years ago
8

If P = h+r, then h = . what is the answer? ​

Mathematics
2 answers:
Elan Coil [88]3 years ago
5 0

Answer:

h = P - r

Step-by-step explanation:

Given

P = h + r ( isolate h by subtracting r from both sides )

P - r = h

Pie3 years ago
4 0

Answer:

h=P-r

Step-by-step explanation:

Hope this helps

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Given z=f(x,y),x=x(u,v),y=y(u,v), with x(1,3)=2 and y(1,3)=2, calculate zu(1,3) in terms of some of the values given in the tabl
stich3 [128]

The value of zu(1,3) using the data elements represented on the table of values is q + p

<h3>How to solve the calculus expression?</h3>

The given parameters are:

z = f(x, y)

x = x(u, v)

y = y(u, v)

Where

x(1, 3) = 2 and y(1, 3) = 2

To calculate zu(1,3), we make use of:

z_u(1,3) = f_x(x,y) * x_u(1,3) +  f_y(x,y) * y_u(1,3)

The values x(1, 3) = 2 and y(1, 3) = 2 mean that:

(x,y) = (2,2).

So, we have:

z_u(1,3) = f_x(2,2) * x_u(1,3) +  f_y(2,2) * y_u(1,3)

From the table of values, we have:

f_x(2,2) = q

x_u(1,3) = 1

f_y(2,2) = 1

y_u(1,3) = p

So, the equation becomes

z_u(1,3) = q * 1 +  1 * p

Evaluate the product

z_u(1,3) = q + p

Hence, the value of zu(1,3) is q + p

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3 0
2 years ago
What is the angle of rotation about the center that will map the regular pentagon onto itself
BlackZzzverrR [31]

Answer:

I think c 430 and if it is wrong I'm so sorry

7 0
3 years ago
2 to the -6 power in expotional form and simplified in fractions
IceJOKER [234]

Answer:

1/64

Step-by-step explanation:

2 ^{ - 6}

1 \div 2 ^{6}

1 \div 64

4 0
2 years ago
Read 2 more answers
Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.
gavmur [86]

The required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

<h3>What is integer?</h3>

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Zero is not a fraction or decimal of any number. It is neither positive nor negative.

Given:

Set D is the set of positive two-digit even numbers less than 25 that do not contain the digit 0.

According to given question we have

2-digit numbers are the numbers that have two digits and they start from the number 10 and end on the number 99.

Starting at 12 going up the two digit numbers even numbers less than 25 that do not contain the digit 0.

12,14,16,18,22,24

Therefore, the required set of positive two-digit even numbers less than 25 that do not contain the digit 0 is 12,14,16,18,22,24.

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1 year ago
PLEASE HELP 30 PTS!!! Select ALL the correct answers. Which expressions are equivalent to the following?
Oksanka [162]

Answer:

  D:  -5(-6x^2 + x + 2)

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Step-by-step explanation:

The <em>first two answer choices have incorrect constants</em> (25 and 3 vs -10). A factor of 5 is removed from the remaining answer choices, so let's remove a factor of 5 and see what we get:

  30x^2 -5x -10 = 5(6x^2 -x -2)

An additional x cannot be factored from the expression, so <em>choice C can be eliminated</em>.

Multiplying each of these factors by -1 will make the product correspond to answer choice D.

Factoring will make it correspond to answer choice E, best verified by finding the x-term of the product of the binomial factors:

  E:  2x(-2) +1(3x) = -x, as required

  F:  2x(2) -1(3x) = x, wrong sign

The equivalent expressions are those of choices D and E.

7 0
3 years ago
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