<span>command delete_all_rights(p, q, s)
delete read from a[q, s];
delete write from a[q, s];
delete execute from a[q, s];
delete append from a[q, s];
delete list from a[q, s];
delete modify from a[q, s];
delete own from a[q, s];
end</span>
Answer:
In a buffer
Explanation:
We can define a buffer as a temporary holding area for data between the various devices and the CPU make I/O synchronization especially if there are multiple devices attempting to do I/O at the same time.
Items stored at the buffer helps to reduce the The incompatibilities in speed between the various devices and the CPU.
A network administrator notices that some newly installed Ethernet cabling is carrying corrupt and distorted data signals. The new cabling was installed in the ceiling close to fluorescent lights and electrical equipment
Two factors may interfere with the copper cabling and result in signal distortion and data corruption are :
EMI
RFI
Explanation:
- EMI (electromagnetic interference) is the disruption of operation of an electronic device when it is in the vicinity of an electromagnetic field (EM field) in the radio frequency (RF) spectrum that is caused by another electronic device.
- During EMC testing, radiated emissions measurements are made using a spectrum analyzer and or an EMI receiver and a suitable measuring antenna.
- EMI (Electromagnetic Interference) is also called RFI (Radio Frequency Interference).
- Conducted RFI is unwanted high frequencies that ride on the AC wave form. Radiated RFI is emitted through the air. There are many pieces of equipment that can generate RFI, variable frequency drives included.
- The internal circuits of personal computers generate EM fields in the RF range.
Answer:
The owls population increased by 13 in one year
Explanation:
The given data on the owl population are as follows;
The number of new owls born = 20 (positive increase in population)
The number of owls that die = 10 (negative decrease in population)
The number of owls that enter the forest = 5 (positive increase in population)
The number of owls that left the forest = 2 (negative decrease in population)
Let 'w' represent the number of new owls born, let 'x' represent the number of owls that die, let 'y' represent the number of owls that enter the forest and let 'z' represent the number of owls that left the forest, we get;
The change in population, ΔP = w - x + y - z
By plugging in the values, we get;
ΔP = 20 - 10 + 5 - 2 = 13
The change in the population of owls in one year is an increase in 13 owls.
Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
