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Triss [41]
3 years ago
12

Write a program that allows the user to enter the last names of five candidates in a local election and the votes received by ea

ch candidate. The program should then output each candidate’s name, the votes received by that candidate. Your program should also output the winner of the election. A sample output is: Candidate Votes Received % of Total Votes Johnson 5000 25.91 Miller 4000 20.73 Duffy 6000 31.09 Robinson 2500 12.95 Ashtony 1800 9.33 Total 19300 The Winner of the Election is Duffy.
Computers and Technology
1 answer:
blsea [12.9K]3 years ago
7 0

Answer:

#include <iostream>

#include <string>

using namespace std;

int main()

{

   string names[5];

   int votes[5];

   for(int i=0;i<5;i++)

   {

       cout<<"Enter candidate name"<<endl;

      getline(cin,names[i]);

       cout<<"Enter candidate votes"<<endl;

       cin >> votes[i];

 cin.ignore();

   }

int total_votes=0;

int max =-1;

int max_val=0;

for(int i=0;i<5;i++)

   {

       total_votes=total_votes+votes[i];

       if(max_val<votes[i])

       {

           max_val=votes[i];

           max=i;

       }

       

   }

   cout<<"Total votes"<<total_votes<<endl;

   for(int i=0;i<5;i++)

   {

       float per=(votes[i]/total_votes)*100;

       cout<<"float per"<<per<<endl;

       cout<<" "<<names[i]<<" "<<votes[i]<<" "<<per<<" %" <<endl;

   }

       cout<<"Winner is  "<<names[max]<<" "<<votes[max]<<endl;

   return 0;

}

Explanation:

Define a string array of size 5 for names. Define one integer array of size 5 for votes. Take input from user in loop for string array and int for votes.

In another loop find maximum of the list and sum all the votes. Store max votes index in max variable. In another loop display names along with their votes and percentage.

Display winner name and votes using max as index for name and votes array.

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Answer:

.data

prompt: .asciiz "Enter 4 integers for A, B, C, D respectively:\n"

newLine: .asciiz "\n"

decimal: .asciiz "f_ten = "

binary: .asciiz "f_two = "

decimal2: .asciiz "g_ten = "

binary2: .asciiz "g_two = "

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#display prompt

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syscall

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syscall

move $t0, $v0

#Read B input in $v0 and store it in $t1

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syscall

move $t1, $v0

#Read C input in $v0 and store it in $t2

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syscall

move $t2, $v0

#Read D input in $v0 and store it in $t3

li $v0, 5

syscall

move $t3, $v0

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#Loop (AxA)

li $t6, 0

L1:

bge $t6, $t0, quit

add $s1, $s1, $t0 # A=S+A => $s1= A^2

addi $t6, $t6, 1 # i=i+1

j L1

quit:

#Loop (A^2 x A^2)

li $t6, 0

L1A:

bge $t6, $s1, quit1A

add $s5, $s5, $s1

addi $t6,$t6, 1

j L1A

#End of Finding A^4

#Finding 4xA^3

quit1A:

#Loop (4xB)

li $t6, 0

L2:

bge $t6, 4, quit2

add $s2, $s2, $t1

addi $t6, $t6, 1

j L2

quit2:

#Loop (BxB)

li $t6 , 0

L2A:

bge $t6, $t1, quit2A #loop2

add $s6, $s6, $t1 #add

addi $t6, $t6, 1 #add immediate

j L2A #loop2

quit2A: # perform proper program termination using syscall for exit

#Loop (BxB)

li $t6 , 0 #load immediate

L2AA:

bge $t6, $s2, quit2AA #loop2

add $t7, $t7, $s6 #add

addi $t6, $t6, 1 #add immediate

j L2AA #loop2

#End ofFinding 4xA^3

#Finding 3xC^2

quit2AA: # perform proper program termination using syscall for exit

#3 Loop (3 x (C x C)) FOR S3

li $t6 , 0 #load immediate

L3:

bge $t6, $t2, quit3 #loop3

add $s3, $s3, $t2 #add

addi $t6,$t6, 1 #add immediate

j L3 #loop3

quit3: # perform proper program termination using syscall for exit

#3 Loop (3 x (C x C)) FOR S3

li $t6 , 0 #load immediate

L3A:

bge $t6, 3, quit3A #loop3

add $s0, $s0, $s3 #add

addi $t6,$t6, 1 #add immediate

j L3A #loop3

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#Finding 2xD

quit3A: # perform proper program termination using syscall for exit

#4 Loop (2 x D) FOR S4

li $t6 , 0

L4:

bge $t6, 2, quit4 #loop4

add $s4, $s4, $t3 #add

addi $t6, $t6, 1 #add immediate

j L4 #Loop4

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quit4:

li $t6, 0

li $s1, 0

L5:

bge $t6, $t1, quit5

add $s1, $s1, $t1

addi $t6, $t6, 1

j L5

quit5:

li $t6, 0

li $s2, 0

L6:

bge $t6, $t0, quit6

add $s2, $s2, $s1

addi $t6, $t6, 1

j L6

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#Finding C^2XD^3

quit6: #finds C^2

li $t6, 0

li $s1, 0

L7:

bge $t6, $t2, quit7

add $s1, $s1, $t2

addi $t6, $t6, 1

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li $t6, 0

li $s6, 0

L8:

bge $t6, $t3, quit8

add $s6, $s6, $t3

addi $t6, $t6, 1

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quit8: #finds D^3

li $t6, 0

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L9:

bge $t6, $t3, quit9

add $s7, $s7, $s6

addi $t6, $t6, 1

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quit9: #finds C^2XD^3

li $t6, 0

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L10:

bge $t6, $s1, end

add $s3, $s3, $s7

addi $t6, $t6, 1

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end: # perform proper program termination using syscall for exit

#f is $t8

li $t8 , 0

sub $t8, $s5, $t7 # addition

add $t8, $t8, $s0 # subract

sub $t8,$t8, $s4 # subract

#g is $t9

li $t9 , 0

add $t9, $s2, $s3 # addition

#Display

#1st equation

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, decimal # Gives answer in decimal value

syscall # value entered is returned in register $v0

li $v0, 1 # display the answer string with syscall having $v0=1

move $a0, $t8 # moves the value from $a0 into $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, binary # Gives answer in binary

syscall # value entered is returned in register $v0

li $v0, 35

move $a0, $t8 # moves the value from into $a0 from $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

#2nd equation

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, decimal2 # Gives answer in decimal value

syscall # value entered is returned in register $v0

li $v0, 1 # display the answer string with syscall having $v0=1

move $a0, $t9 # moves the value from $a0 into $t8

syscall # value entered is returned in reg $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, binary2 # Gives answer in binary

syscall # value entered is returned in register $v0

li $v0, 35

move $a0, $t9 # moves the value from into $a0 from $t8

syscall # value entered is returned in register $v0

li $v0,4 # display the answer string with syscall having $v0=4

la $a0, newLine # puts newLine in between answers

syscall # value entered is returned in register $v0

#end the program

li $v0, 10

syscall

8 0
3 years ago
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