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s344n2d4d5 [400]
3 years ago
11

Find an equation for the perpendicular bisect or of the line segment whose end points are (-2,-4) and (8,2)

Mathematics
1 answer:
Serhud [2]3 years ago
4 0

Answer:

, you must find the midpoint of the segment, the formula for which is

(

x

1

+

x

2

2

,

y

1

+

y

2

2

)

. This gives

(

−

5

,

3

)

as the midpoint. This is the point at which the segment will be bisected.

Next, since we are finding a perpendicular bisector, we must determine what slope is perpendicular to that of the existing segment. To determine the segment's slope, we use the slope formula

y

2

−

y

1

x

2

−

x

1

, which gives us a slope of

5

.

Perpendicular lines have opposite and reciprocal slopes. The opposite reciprocal of

5

is

−

1

5

.

We now know that the perpendicular travels through the point

(

−

5

,

3

)

and has a slope of

−

1

5

.

Solve for the unknown

b

in

y

=

m

x

+

b

.

3

=

−

1

5

(

−

5

)

+

b

⇒

3

=

1

+

b

⇒

2

=

b

Therefore, the equation of the perpendicular bisector is

y

=

−

1

5

x

+

2

.

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victus00 [196]

Answer:

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