I use the substitution method, but you can also use elimination and matrix
1. Solve for y in 3x+y=14
y=14-3x
2. Substitute y=14-3x into x+2y=3
-5x+28=3
3. Solve for x in -5x+28=3
x=5
4. Substitute x=5 into y=14-3x
y=-1
5. Therefore,
x=5
y=-1
Have a nice day :D
Here is how you would set it up...
You would to 12/100 = x/2 and cross multiply and solve by division. I believe. I'm almost positive that's how you do it. If that don't work out, comment and I'll respond.
Answer:
136000×2000\8×100 do like that the answer is come
To determine when Mya will have both lessons again on the same day, you will list the multiples of each number of days because to show every 4 or 6 days, you will count by 4's and 6's.
When you get to the first number that is the same, that will be the next time she will have both lessons again. This is called the least common multiple (LCM).
4, 8, 12, 16, 20, ...
6, 12, 18, 24
In 12 days she will have both lessons again.