Answer:
The chance of getting exactly 3 hits is = 0.20
Step-by-step explanation:
P.S - The exact question is -
As given,
F(x) = 0 , x < 1
0.30 , 1 ≤ x < 2
0.56 , 2 ≤ x < 3
0.76 , 3 ≤ x < 4
0.9 , 4 ≤ x < 5
1 , 5 ≤ x
Now,
f(x) = 0.30 , x = 1
0.56 - 0.30 = 0.26 , x = 2
0.76 - 0.56 = 0.20 , x=3
0.9 - 0.76 = 0.14 , x = 4
1 - 0.9 = 0.1 , x = 5
0, otherwise
Now,
The chance of getting exactly 3 hits is = f(x = 3) = 0.20
Answer:
Yes, because P = 2x +2(12)
Step-by-step explanation:
As the formula for perimeter is 2(L+B).
Let L=x=18
B=12
Then, perimeter, P=2(18+12) = 2(30) = 60
Hence, we get the perimeter as 60 units.
I am assuming you're doing a Punnet square, so you multiply each one. So on the top left box, it is -45x^2, the top right is 9x, bottom left is 35x, and bottom right is -7.
8+5+8=21 coins in total.
8/21*7/20=
56/420=
2/15. Hope this helps, and PM me if something's not clear!
In the binomial expansion of (0.30+0.70)²⁰ the coefficient is ²⁰C₁₀=184756 for x=10 and we have 0.30¹⁰×0.70¹⁰ for the pq values where q=1-p. This comes to about 0.03. So the statement p(x=10)=0.50 is false, answer b.
