Select all ordered pairs that satisfy the function y=-3x+5

PLEASE HELP WILL MARK BRAINLIEST

Kipish [7]

Answer:

Step-by-step explanation:

x^2 = 64

√x² = √64

x = 8, -8

answer is B

5 0

3 years ago

What is the amplitude of the function?

Licemer1 [7]

Answer:

2

Step-by-step explanation:

Take the absolute value of the lowest y value.

So

$| - 1| = 1$

Take the absolute value of highest y value.

$|3| = 3$

Add those two together and divide by two.

$\frac{1 + 3}{2} = 2$

So the amplitude is 2

5 0

2 years ago

The function f(x) = −x2 − 9x + 10 shows the relationship between the vertical distance of a diver from a pool's surface f(x), in

mote1985 [20]

Answer:

Zeros of a function: x = 1 and x = -10

Step-by-step explanation:

A zero of a function is the value of x when f(x) = 0. In other words it is the intersect point between x and y=f(x), when y =0.

First we need to make f(x)=0, so we would have: $-x^{2}-9x+10=0$ .

If we factorize this quadratic function, we would have: $(x+10)(x-1)=0$

So we get x = -10 and x = 1.

x = 1 means that the diver hits the water 1 foot away horizontally from the board.
x=-10 means the diver hits the water 10 feet behind the diving board.

Hope it helps!

4 0

4 years ago

To eliminate the y terms, you can multiply the first equation by 5 and the second equation by what number?

gladu [14]

Step-by-step explanation:

the second equation should be multiplied by 9

6 0

3 years ago

1. Write the equation of the piece-wise function graphed below.

DaniilM [7]

Problem 4

<h3>Answer:</h3>

$f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}$

------------------

Work Shown:

The left line goes through (-2,0) and (0,4)

The slope of this line is

m = (y2-y1)/(x2-x1)

m = (4-0)/(0-(-2))

m = (4-0)/(0+2)

m = 4/2

m = 2

The y intercept is b = 4

Since m = 2 and b = 4, this means y = mx+b turns into y = 2x+4. This portion is only done when x < 1. Note the open circle at the endpoint of this portion. So we do not include x = 1 as part of this piece.

---

The line on the right side goes through (1,-2) and (2,-1)

Slope

m = (y2-y1)/(x2-x1)

m = (-1-(-2))/(2-1)

m = (-1+2)/(2-1)

m = 1/1

m = 1

The y intercept is b = -3. You can see this if you extend the line until it crosses the y axis.

Alternatively, plug in (x,y) = (1,-2) and m = 1 into y = mx+b to find that b = -3

So y = mx+b turns into y = 1x+(-3) or just y = x-3

We combine both parts to end up with $f(x) = \begin{cases}2x+4 \text{ if } x < 1\\x-3 \text{ if } x \ge 1\end{cases}$

This is only graphed when $x \ge 1$ (note the closed or filled in circle for the endpoint of this portion).

===================================================

Problem 5

Answer:

<h3> $f(x) = \frac{1}{2}|x+3|$ is the absolute value function</h3><h3>while this is the piecewise function</h3>

$f(x) = \begin{cases}-\frac{1}{2}(x+3) \text{ if } x < -3\\\frac{1}{2}(x+3) \text{ if } x \ge -3\end{cases}\\$

------------------

Work Shown:

y = |x| .... parent function

y = |x+3| ... shift 3 units to the left

y = (1/2)*|x+3| .... vertically compress by factor of 1/2

f(x) = (1/2)*|x+3|

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Break that down into a piecewise function

when x < -3, then y = -(1/2)(x+3)

when $x \ge -3$ , then y = (1/2)(x+3)

I'm using the rule that y = |x| turns into y = -x when x < 0 and y = x when $x \ge 0$

So that is how we get $f(x) = \begin{cases}-\frac{1}{2}(x+3) \text{ if } x < -3\\\frac{1}{2}(x+3) \text{ if } x \ge -3\end{cases}\\$ as the piecewise function.

8 0

3 years ago

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