Answer:
30th term is
9(30+3) =270+27=297
to find the first term which is larger than 100
9(n+3) =100
9n=100-27
9n=73
n=73÷9
=8.1
so when n is>8.1 all the terms will be larger than 100 and the first term will be 9 since n can't be fraction as it's an ordinary number
so it's 9th
9(9+3) =81+27=108
the first four terms are
9(1+3) =36
9(2+3) =45
9(3+3) =81
9(4+3) =63
Step-by-step explanation:
n(n-1)
the first four terms are
1(1-1) =0
2(2-1) =2
3(3-1) =6
4(4-1) =12
the 10th term is 10(10-1) =90
to find weather 51 is a term or not
n(n-1) =51
n^2-n-51=0
1-4×1×-51=1+204=205
so it's roots will be fraction
so it's not from its terms because n will
be fraction
to find the term 182
n(n-1) =182
n^2-n-182=0
(n-14) (n+13)=0
so it's the term 14th because n can't be negative
Answer:
6
Step-by-step explanation:
Your function is split into 4 parts.
We want to use the piece that includes x=6.
This only included in the inequality that says x is greater than or equal to 5. Since that is, we use the expression that corresponds to that to find f(6).
f(6)=2(6)-6
f(6)=12-6
f(6)=6
Answer:
Yes
Step-by-step explanation:
You can conclude that ΔGHI is congruent to ΔKJI, because you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K).
We also know that we have two congruent sides, since it provides the information that line GK bisects line HJ, meaning that they have been split evenly (they have been split, with even/same lengths).
<u><em>So now we have three congruent angles, and two congruent sides. This is enough to prove that ΔGHI is congruent to ΔKJI,</em></u>
<u><em /></u>
The Area of rectangle = 80 unit².
<h3>What is Area of rectangle?</h3>
The area can be defined as the amount of space covered by a flat surface of a particular shape. It is measured in terms of the "number of" square units (square centimeters, square inches, square feet, etc.) The area of a rectangle is the number of unit squares that can fit into a rectangle. Some examples of rectangular shapes are the flat surfaces of laptop monitors, blackboards, painting canvas, etc. You can use the formula of the area of a rectangle to find the space occupied by these objects. For example, let us consider a rectangle of length 4 inches and width 3 inches.
from figure (a)
DE= 40/8 = 5
BC= 100/5 = 20
Now,
AC= AB + BC= 8+ 20 = 28
CE= CD + DE = 10+5= 15
So, area of rectangle
= AC* CE
= 28* 15
= 420
Now, from figure (b)
CD= 24/12= 2
DE= 12/4 = 3
AC= AB+ BC= 14+ 4= 16
CE= CD + DE= 2+3 = 5
So, Area of rectangle= 16*5 = 80 unit²
Learn more about area of rectangle here:
brainly.com/question/237997
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The equation is
.
If p = 17, f = 13. This value is a reasonable value in this context.
If f = 28, p = -10. This value is not reasonable in this context.
Step-by-step explanation:
Step 1:
,
where p is the part-time memberships and f is the number of full-time memberships.
Kiri needs to make $5,050 a month from this rented space.
Each part-time membership costs $155 and each full-time membership costs $225.
Step 2:
We need to calculate the value of f when p = 17,
Substituting the value, p = 17 in the equation, we get;
, 

The value of f = 13 and p = 17. This is a reasonable value in this context.
Step 3:
We need to calculate the value of p when f = 28,
Substituting the value, f = 28 in the equation, we get;
, 

The value of f = 28 and p = -10. This is not a reasonable value in this context. as the values of f and p cannot be negative for this given equation.